验证文本框 [英] Validation Of TextBox

问题描述

你好朋友，
我正在对表单进行验证，我有一个问题.
我必须验证这样的文本框，使其仅接受6到8位之间的字母数字值.
如12345a或asdgfg67
在此先感谢

Hello Friends,
I am doing validation on my form ,i have a problum.
i have to validate a textbox like this that it will take only alphnumeric values in between 6 to 8 digits.
like 12345a or asdgfg67
Thanks In Advance

推荐答案

仅将Ajax的过滤器文本框扩展器用于字母数字，并且对最大值和最小值进行范围验证

Use Filter Textbox Extender of Ajax for only alphanumeric and Range validation for Max and min value

<cc1:FilteredTextBoxExtender ID="txtMobile_FilteredTextBoxExtender"

                 runat="server" Enabled="True" TargetControlID="txtMobile"

                 ValidChars="0123456789abcdefghijklmnopqrstuvwxyz">
             </cc1:FilteredTextBoxExtender>

< asp:TextBox ID ="TextBox1" runat ="server"></asp:TextBox>

<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>

<asp:RangeValidator ID="RangeValidator1" runat="server"

                ControlToValidate="TextBox1" ErrorMessage="RangeValidator" MaximumValue="8"

                MinimumValue="6"></asp:RangeValidator>

这是Java脚本.希望这项工作有效

函数ValidateAlphaNumeric(ctrlID，ctrlName)
{
var password = document.getElementById(ctrlID).value;

if(密码！=")
{
var checkNumber = 0，checkAlpha = 0;

for(count = 0; count< password.length; count ++)
{
if((password.charAt(count)< ="z" && password.charAt(count)> ="a")||(password.charAt(count)< ="Z" && password.charAt(count )> ="A"))
{
checkAlpha = 1;
}
否则if((password.charAt(count)< ="8" && password.charAt(count)> ="6"))
{
checkNumber = 1;
}
}
}
其他
{
返回true;
}

Here is the Java script..Hope this works

function ValidateAlphaNumeric(ctrlID, ctrlName)
{
var password = document.getElementById(ctrlID).value;

if(password != "")
{
var checkNumber=0,checkAlpha=0;

for(count=0 ; count < password.length ; count++)
{
if((password.charAt(count) <= "z" && password.charAt(count) >= "a") ||(password.charAt(count) <= "Z" && password.charAt(count) >= "A"))
{
checkAlpha = 1;
}
else if((password.charAt(count) <= "8" && password.charAt(count) >= "6"))
{
checkNumber = 1;
}
}
}
else
{
return true;
}

I think when you get the input of password,
first, validate the length between 6-8;
second,validate each char of the input-string, using regular expressions '\w'.
good luck!

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