c的增量和加法 [英] increement and addition in c

问题描述

#include <stdio.h>
int main(int argc, char** argv)
{
   int x = 3;
   printf("%d ";, x++ + ++x);
   return 1;
}</stdio.h>

请，我需要知道为什么输出会是8，因为我认为必须是7?

Please, I need to know why the output will be 8 since I think it has to be 7?

推荐答案

感谢您对Mamun的回复
但我想问个问题
我知道x ++在printf期间不会递增3，但是在它之后并另存为x = 4，这就是加法运算，这意味着直到现在我们有了3+，然后才是++ x，首先是递增x，所以x现在将是5，因为它是4，并且增加了1
最后我们有3 + 5 = 8

这是你的意思吗
谢谢:)

thanks for ur reply Mamun
but i want to ask something
i know that x++ here won''t increment 3 during printf but after it and save as x=4 then comes the addition operation this means till now we have 3+ then comes the ++x and this increment x firstly so x now will be 5 beacause it was 4 and increased by 1
finally we have 3+5=8

is this what u mean
thanks :)

谢谢您的提问，

Than you for your question,

int x = 3; //now three
printf("%d ";, x++ + ++x); // in the line
x++ means 3 + 1 = 4
++x this statement will decrease 1 from 4 but after addition.
so, x++ + ++x will be 8. 

谢谢，
马蒙

Thanks,
Mamun

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