使用结构帮助C#get {}和set {} [英] Help with C# get{} and set{} using structs

问题描述

我在C#中使用get{}和set{}时遇到问题(用于自定义控件).通常，如果我声明一个变量，它会按预期显示在属性框中，并且可以相应地进行设置.但是，如果我创建一个结构，它只是拒绝让我编辑字段.我的代码如下:

  public   struct  myInts
        {
            私有  int  myX，myY，myZ；

             public  myInts( int  x， int  y ， int  z)
            {
                myX = x;
                myY = y;
                myZ = z;
            }

            公共  int  X
            {
                获取 {返回 myX; }
                 set  {myX =  value ; }
            }
            公共  int 是
            {
                获取 {返回 myY; }
                 set  {myY =  value ; }
            }
            公共  int  Z
            {
                获取 {返回 myZ； }
                 set  {myZ =  value ; }
            }

            公共 覆盖 字符串 ToString()
            {
                返回(myX + "  + myY + "  + myZ);
            }
        }

        私有 myInts整数= 新 myInts( 1  ， 2 ， 3 )；
        公共 myInts MyIntegers
        {
            获取 {返回整数； }
             set  {整数= 值; }
        } 

它显示在属性框中，但是不能展开和编辑.任何帮助将不胜感激

解决方案

凯尔，

您需要一个自定义的属性编辑器.
看这里:
http://msdn.microsoft.com/en-us/library/ms171839.aspx

我会选择TypeConverter方法，因为它不应该太
很难将结构转换为字符串然后返回，但这只是我的
个人意见.

干杯

曼弗雷德(Manfred)

不是真正的答案-抱歉

我刚刚在MyIntegers属性中添加了[TypeConverter(typeof(ExpandableObjectConverter))]属性，它向我显示了属性网格中的值，但是我无法更改它们，按Enter后它们将重置为原始值.我意识到设计师无法以这种方式序列化它.如果我将结构更改为可以工作的类(添加默认ctor之后.您是否真的需要将其保留为结构?

为什么一定要创建您类型的属性?

哪些已经具有属性?

就这样使用您的类型...
您可以删除公共myInts MyIntegers属性.

 静态  void  Main(字符串 []参数)
{
  myInts整数= 新 myInts( 5 ， 5 ， 5 )；
  Console.WriteLine(integer.ToString());
  integer.X =  10 ;
  Y =  10 ;
  integer.Z =  10 ;
  Console.WriteLine(integer.ToString());
  Console.ReadKey();
} 

写入控制台:

"5, 5, 5"

"10, 10, 10"

I am having a problem using get{} and set{} in C# (it''s for a custom control). Generally, if I declare a variable, it shows up in the property box as expected, and can be set accordingly. If, however, I create a struct, it simply refuses to let me edit the fields. My code is as follows:

public struct myInts
        {
            private int myX, myY, myZ;

            public myInts(int x, int y, int z)
            {
                myX = x;
                myY = y;
                myZ = z;
            }

            public int X
            {
                get { return myX; }
                set { myX = value; }
            }
            public int Y
            {
                get { return myY; }
                set { myY = value; }
            }
            public int Z
            {
                get { return myZ; }
                set { myZ = value; }
            }

            public override string ToString()
            {
                return (myX + ", " + myY + ", " + myZ);
            }
        }

        private myInts integers = new myInts(1, 2, 3);
        public myInts MyIntegers
        {
            get { return integers; }
            set { integers = value; }
        }

It is displayed in the property box, but cannot be expanded and cannot be edited. Any help will be much appreciated

解决方案

Hi Kyle,

You''d need a custom property editor for that I''d say.
Look here:
http://msdn.microsoft.com/en-us/library/ms171839.aspx

I would go for the TypeConverter method, since it shouldn''t be too
hard to convert a struct to string and back, but that''s just my
personal opinion.

Cheers

Manfred

Not realy an answer - sorry

I just added the [TypeConverter(typeof(ExpandableObjectConverter))] attribute to the MyIntegers property and it showed me the values in the property grid, but I couldn''t change them, they were reset to the original ones after pressing enter. I realized the designer couldn''t serialize it this way. If I changed the struct to a class it worked (after adding a default ctor. Do you realy need to hold it as struct?

Why do you necessarily want to make a property of your type which already has properties?

Just use your type as such...
Your can remove your public myInts MyIntegers property.

static void Main(string[] args)
{
  myInts integer = new myInts(5,5,5);
  Console.WriteLine(integer.ToString());
  integer.X = 10;
  integer.Y = 10;
  integer.Z = 10;
  Console.WriteLine(integer.ToString());
  Console.ReadKey();
}

Writes to console:

"5, 5, 5"

"10, 10, 10"

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