C#应用程序充当Magic 8球 [英] C# Application to act as a Magic 8 ball

问题描述

你好，

该网站的新手和C#在一起.

我想知道如何制作Magic 8球的业余版本.
我需要提供的所有帮助是:如何生成随机的是和否答案?

用户将输入一个随机问题，那么我希望应用程序给出一个随机的是和否.

非常感谢您的帮助！

-G

Hello,

New to this site and C# all together.

I was wondering how I could build a amateur version of a Magic 8 ball.
All I need help on is this: How do I generate a random yes and no answer?

The user would input a random question and well I want the application to give a random yes and no.

Thank you very much for the help!

-G

推荐答案

Random rnd = new Random();

if((rnd.Next() & 1) == 0)
{
    // Yes ...
}
else
{
   // No
}

这通过检查是否未设置最低位(整数为偶数)来工作，但您也可以检查是否设置了位(== 1，等于奇数).

另一种可行的方法是％(取模运算符)，它给出余数.
x％n给出x除以n的余数:例如X = 6 N = 3
6％3 == 0

如果您需要两个以上的是"和否"选项，这将非常有用.
例如:

0 ==是"
1 ==否"
2 ==稍后再问"
3 ==不太可能"

This works by checking if the lowest bit is not set (integer is even) but you could also check if bit is set ( == 1 which amounts to odd).

Another way to go is % (modulo operator) which gives the remainder.
x % n gives the remainder of the division of x by n: e.g X = 6 N = 3
6 % 3 == 0

This is very usefull if you need more than the 2 options "yes" and "no".
For example:

0 == "Yes"
1 == "No"
2 == "Ask again later"
3 == "Not very likely"

int numberOfChoices = 4;
Random rnd = new Random();
switch(rnd % numberOfChoices)
{
    case 0:
        //"Yes" stuff goes here
        break;
    case 1:
        //"No" stuff goes here
        break;
    case 2:
        //"Ask again later" stuff goes here
        break;
    case 3:
        //"Not very likely" stuff goes here
        break;

}

干杯

Manfred

Cheers

Manfred

Google is your friend

You should always start with a simple search on google because most beginner questions will already have answers out there.

Cheers

Random rand = new Random();
int i = rand.Next(2); // generates numbers between 0 and 1

string strYesOrNo = (i == 0) ? "yes" : "no";

这篇关于C#应用程序充当Magic 8球的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！