帮助并非所有代码路径都返回值 [英] HELP Not all code paths return a value

问题描述

好吧，我使用代码

Well im using the code

public static MySqlConnection GetConnection(string server, string user, string password, string db)
{
    string str = "Server='" + server + "';user='" + user + "';password='" + password + "';database='" + db + "';";
    MySqlConnection con = new MySqlConnection(str);
    con.Open();
    isConnected = true;
}

而且我似乎无法弄清楚为什么它会给我错误:并非所有代码路径都返回一个值，我想知道是否有人可以通过this

And i cant seem to figure out why its giving me the error :Not all code paths return a value, i was wondering if someone could help me out with this

推荐答案

您需要返回类型为MySqlConnection的对象.在这种情况下，它应该是con.

You need to return an object of type MySqlConnection. In this case that would be con.

该方法必须返回一个MySqlConnection对象. 大概

That method must return a MySqlConnection object.
Probably

return con;

只需在大括号前即可解决问题.
:rolleyes:

just before the closing curly bracket will do the trick.
:rolleyes:

问题是，您没有返回MySqlConnection.您可以做的是:

the problem is, that you are not returning a MySqlConnection. What you could do is:

public static MySqlConnection m_con;

public static MySqlConnection GetConnection(string server, string user, string password, string db)
{
    string str = "Server='" + server + "';user='" + user + "';password='" + password + "';database='" + db + "';";
    m_con = new MySqlConnection(str);
    con.Open();
    isConnected = true;
    return m_con;
}

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