单击图像获取鼠标位置 [英] Get Mouse Location at Click on a Image

问题描述

这是我目前如何在图片框中的图像上获得X和Y位置(图像设置为正常)

Hi this is how I currently get the X and Y location on A image in a Picture Box (Image is set To normal)

Dim xmouse as int16
Dim ymouse as int16

Private Sub PBData_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles PBData.Click
'Take the click point - The location of the Windows - the Location of the Picturebox in the Window.
     xmouse = MousePosition.X - Me.Location.X - 313
     ymouse = MousePosition.Y - Me.Location.Y - 99
     XLOC.Text = xmouse
     Yloc.Text = ymouse

 End Sub

想知道是否有更好的方法吗?

基本上我用它来获得较大图像中单击的子图像
并且仅显示其裁剪版本并显示附加值.

and wanted to know if there is a better way to get it?

Basically I used it the get the Sub Image Clicked on in the Larger Image
and Displays just a cropped version of it and displays a attached value.

推荐答案

U可以改用它吗?


Dim xmouse as int16
昏暗的ymouse作为int16

Can U use This instead


Dim xmouse as int16
Dim ymouse as int16

Private Sub PBData_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles mouse.Click

     xmouse = e.X - Me.Location.X - 313
     ymouse = e.Y- Me.Location.Y - 99
     XLOC.Text = xmouse
     Yloc.Text = ymouse

 End Sub

U可以解释为什么U使用313和99相减吗??



:cool :: cool:

Can U explain Why are U using 313 and 99 to be subtracted???



:cool::cool:

O是我的PicureBox的起点已与我的表单相对(可以使用位置，并且可以减去X和Y)

PBData的X = 313
YData的Y = 99

O that is the start point of my PicureBox Compaired to my Form (Location can be use and X and Y subtracted)

PBData''s X= 313
YData''s Y= 99

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