弹出框，显示简要信息(如工具提示) [英] Popup box showing brief information(like tooltip)

问题描述

我正在通过代码将搜索结果数据动态绑定到Listview中.列表视图具有3列，即名称，年龄，位置.现在，我必须实现一个弹出框，如果用户将鼠标悬停在名称"字段上，该框将显示记录的简短摘要.

您能告诉我我该如何实现吗?

谢谢，

Vasanth

Hi,

I am binding the search result data into Listview dynamically through code. List view having 3 columns namely Name, Age,Position. Now i have to implement a popup box which displays brief summary of the record if the user mouses over the "Name" field.

Could you please let me know how do i achieve this?

Thanks,

Vasanth

推荐答案

我认为您是说您拥有一个动态绑定的Datagrid，并且如果用户将鼠标悬停在名称字段上，则希望显示其他信息. br/>
阅读:面向初学者的简单DataGrid行工具提示. [

I think you are saying that you have a Datagrid that you are binding dynamically and you want to show additional information if the user mouses over the name field.

Read: A Simple DataGrid Row Tooltip For Beginners.[^]

If that doesn''t work for you, I can try to work up an example or show you how I do it.

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