如何基于表中的列数据创建动态列 [英] how to create dynamic columns based on column data in a table

问题描述

请帮我，我想基于表格中的列数据动态创建gridview列.

pls help me i want to create gridview columns dynamically based on the column data in a table

推荐答案

嗨 皮拉(Pyla)，

请执行以下操作:

1.在您的datagrid中设置AutoColumn = True
2.根据您的逻辑创建列，如

Hi Pyla,

Please do the following:

1. set AutoColumn=True in your datagrid
2. create columns based on your logic like

DataTable dt = new DataTable();
        for (int c = 1; c <= 10; c++)
        {
            DataColumn dc = new DataColumn("Column" + c.ToString(), System.Type.GetType("System.String"));
            dt.Columns.Add(dc);
        }

        GridView1.Datasource = dt;
        GridView1.DataBind();

如有任何疑问，请让我知道.

如果对您有帮助，请提供投票.

谢谢，
Imdadhusen

Please do let me know, if you have any doubt.

Please provide Vote if this would be helpful to you.

Thanks,
Imdadhusen

公共静态数据表dtValues;

public static DataTable dtValues;

protected void CreateDataTable()
       {
           dtValues = new DataTable();
           dtValues.Columns.Add("Id");
           dtValues.Columns.Add("Item");
           dtValues.Columns.Add("Rate");
           dtValues.Columns.Add("Qty");
           dtValues.Columns.Add("Amount");
       }

这5列将动态创建

比添加它

these 5 columns will be created dynamically

than add it

gvOrders.DataSource = dtValues;
                gvOrders.DataBind();

希望能奏效..
Amit

hope that works..
Amit

检查此代码项目文章如何在网格视图中动态创建列 [ ]

check this codeproject article how to create columns dynamically in a grid view[]

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