如何处理发生故障的析构函数? [英] How can I handle a destructor that fails?

问题描述

如何处理发生故障的析构函数?

How can I handle a destructor that fails?

推荐答案

析构函数从定义上讲不会失败.一旦析构函数运行了对象的死对象，死对象，死对象，并且什么也无法使它再次移动(例如，不同于Java终结器，它可以使对象复活).

这样做的另一个影响是不要将异常抛出析构函数或调用std :: unexpected(IIRC)，通常调用std :: terminate会杀死程序.

只是出于兴趣而已...有多种方法可以从析构函数中获取信息，但是如果您诉诸于使用它们，通常(但并非总是如此)意味着您的类设计有问题.问问自己您在可能会失败的析构函数中做什么，以及如果它不是在析构函数中发生，您将如何处理?

干杯，

Ash

Destructors can''t fail by definition. Once the destructor has run the object''s dead, dead, dead and nothing can get it moving again (unlike a Java finaliser, for example, which can resurrect an object).

An additional impact of this is don''t throw exceptions out of a destructor or std::unexpected (IIRC) is called which usually calls std::terminate which kills your program.

Just out of interest... There are ways of getting information out of a destructor but if you resort to using them it usually (but not always) means there''s something wrong with your class design. Ask yourself what you''re doing in a destructor that can fail and what would you do about it if it wasn''t happening in a destructor?

Cheers,

Ash

清理(尽可能多地)，记录遇到错误的事实，但不要抛出异常！请参见此处 [

Clean up (as much as you can), log the fact that you got hit the error, but do not throw an exception! See here[^] for details. :)

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