设为上传者 [英] make uploader

问题描述

我必须在gridview中创建一个超链接按钮，因为当我单击它时，将打开其他gridview，其中包含所选

i have to make a hyperlink button in gridview because when i will click on it then other gridview will be open with full record of the selected

推荐答案

的完整记录

不要去超链接，去去链接按钮...
将网格视图放置在顶部网格项目模板内，然后单击链接按钮使可见性为false，以使网格编辑事件中的网格可见性为真.

问候
Vinay

Hi,

Don''t go for hyperlink go for a link button...
Place a Grid view inside the top grid item template and make the visibility false on click of the link button make the grid visiblity true in grid edit event.

Regards
Vinay

您所说的是主从网格视图:
使用GridView进行多层嵌套的主数据/明细数据显示 [ GridView内联主/详细记录显示 [ http://www.progtalk.com/viewarticle.aspx?articleid=1&title = rajib％20a. [ ^ ]

What you are talking of is a Master-Detail Gridview:
Multilevel Nested Master/Detail Data Display Using GridView[^]
GridView inline Master/Detail record display[^]
http://www.progtalk.com/viewarticle.aspx?articleid=1&title=rajib%20a.[^]

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