SQL“计数不相同" [英] SQL 'count distinct'

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本文介绍了SQL“计数不相同"的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一张表,上面有调查答复.每个记录都有一个评分者,评分者以及评分者与评分者之间的关系类型.如何获得每个被评估人的每种评估人的数量?

这应该很容易,但是我处于压力之下并且头脑冻结.

I have a table with survey response answers. Each record has a ratee, rater, and the type of relation between ratee and rater. How do I get the count of each kind of rater per ratee?

This should be easy, but I''m under preasure and having a brain freeze.

推荐答案

SELECT        Ratee, Rater, COUNT(Rater) AS RaterCount
FROM            Results
GROUP BY Ratee, Rater



听起来如何?



How does that sound?


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