获取文件的android系统中的路径 [英] get the path of file in android

问题描述

您好，我们有文件选择器，并希望在与文件选择器的用户选择文件，上传返回所选文件的路径。现在我要怎样才能得到所选文件的路径。我想要的文件这样的路径 - > /mnt/sdcard/DCIM/13.jpg

code：

 私人无效fnFileChooser（）{
    意向意图=新意图（Intent.ACTION_GET_CONTENT）;
    intent.setType（* / *）;
    intent.addCategory（Intent.CATEGORY_OPENABLE）;
    尝试{
        startActivityForResult（
                Intent.createChooser（意向，选择要上传的文件），
                fileSelected code）;
    }
    赶上（android.content.ActivityNotFoundException前）{
    //直接潜在用户市场提供一个对话
    Toast.makeText（这一点，请安装一个文件管理器。
            Toast.LENGTH_SHORT）.show（）;
    }
}
@覆盖
保护无效的onActivityResult（INT申请code，INT结果code，意图数据）{
            如果（结果code == RESULT_OK）{
                //获取所选文件的URI
                URI URI = data.getData（）;
                PATH = uri.getPath（）;
                txtAddress.setText（uri.getPath（））;
                ImageView的IMG =（ImageView的）findViewById（R.id.imgTest）;
                img.setImageURI（URI）;
                / *字符串路径= FileUtils.getPath（这一点，URI）;
                Log.d（TAG，文件路径：+路径）; * /
                //获取文件的实例
                //文件文件=新的文件（路径）;
                //启动上传
            }
    super.onActivityResult（要求code，结果code，数据）;
}
 

解决方案

尝试使用这些code拿到哪一个是 openFileOutput 的

 公共字符串getFilePath（上下文的背景下，字符串YourFileName）
        {
            文件F = context.getFileStreamPath（YourFileName）;
            返回f.getAbsolutePath（）;
        }
 

hello we have file picker and want when user select file with file picker , return path of selected file for upload. now i want how can get path of selected file . i want the path of file like this -- > /mnt/sdcard/DCIM/13.jpg

code :

private void fnFileChooser(){
    Intent intent=new Intent(Intent.ACTION_GET_CONTENT);
    intent.setType("*/*");
    intent.addCategory(Intent.CATEGORY_OPENABLE);
    try{
        startActivityForResult(
                Intent.createChooser(intent, "Select a File to Upload"),
                fileSelectedCode);
    }
    catch (android.content.ActivityNotFoundException ex) {
    // Potentially direct the user to the Market with a Dialog
    Toast.makeText(this, "Please install a File Manager.",
            Toast.LENGTH_SHORT).show();
    }
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {


            if (resultCode == RESULT_OK) {
                // Get the Uri of the selected file
                Uri uri = data.getData();
                path=uri.getPath();
                txtAddress.setText(uri.getPath());
                ImageView img=(ImageView) findViewById(R.id.imgTest);
                img.setImageURI(uri);
                /*String path = FileUtils.getPath(this, uri);
                Log.d(TAG, "File Path: " + path);*/
                // Get the file instance
                // File file = new File(path);
                // Initiate the upload
            }


    super.onActivityResult(requestCode, resultCode, data);
}

解决方案

Try to use these code to get the path of file which one is created with openFileOutput

public String getFilePath(Context context,String YourFileName)
        {
            File f= context.getFileStreamPath(YourFileName);
            return f.getAbsolutePath();
        }

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