如何在不区分大小写的情况下从文本文件中找到单词... [英] How Can I Find A Word From Text File Without Case-Sensitivity ...

问题描述

如何在不区分大小写的情况下从文本文件中找到单词...例如，我必须在文本文件中找到单词" C row". .但是存在" c 行" ...那么我怎么能找到这个词. 我不知道用户会输入 CROW ， Crow ， crow ， croW ， crOW 等，但我希望该用户输入它，答案将是相同的(应打印文本文件中的相同单词)
例如，我有一个代码可以从行的开头查找任何单词:

How can I find a word from text file without case-sensitivity ...For example I have to find the word "Crow" in text file...but there exists "crow"...Then how can I find that word.???
I don''t know that user will enter CROW , Crow , crow, croW , crOW , etc. but I want that user enter it and answer will be same (Same word from text file should be printed)
For Example I have a code to find any word from the starting of line :

void meaning()
        {
            ifstream input( "all.txt" );
            for(string line; getline( input, line ); )
                {
                    if (line.find("crow") == 0)
                    {
                        cout<<line<<endl;
                    }
                }
        }

这里的单词"是用户给出的任何单词...请帮助我解决问题....

Here "word" is any word given by user...Please help me to solve problem....

推荐答案

以下函数比较两个字符串，不区分大小写:

The following function compares two strings without any case sensitivity:

bool CompareWithoutCaseSensitivity(string s1, string s2)
{
    bool r = false;
    string tmp = "", tmp2 = "";
    int i;
    for (i = 0; i < s1.length(); i++)
    {
        tmp = tmp + (char)toupper(s1.at(i));
    }
    for (i = 0; i < s2.length(); i++)
    {
        tmp2 = tmp2 + (char)toupper(s2.at(i));
    }
    return (tmp == tmp2);
}

如果发现任何缺陷，可以改进此代码.我刚刚写了它，但我不能保证这是最好的方法.

You can improve this code if you find any defects. I wrote it just now and I can''t assure you this is the best method.

要查找不区分大小写的单词，请同时更改从文件和word中读取的内容所有的帽子.然后使用strcmp.

To find a word without case sensitivity, change both what you read from the file and word to all caps. Then check the equality with strcmp.

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