如何分割两个字符串 [英] how to split two strings

问题描述

我有字符串=("\" 20v2015-04-13 \")


我需要
的形式
字符串strvalue = 20;
字符串strDate = 2015-04-13;

Hi,

I have the string = ("\"20v2015-04-13\"")


i need it in the form of

string strvalue= 20;
string strDate=2015-04-13;

How is it possible?

推荐答案

使用正则表达式:

Use a regex:

(?<value>\d+)[a-zA-Z](?<date>\d{4}-\d\d-\d\d)</date></value>

应该做的-将数据提取为值"和日期"两类，您可以在没有剩余垃圾的情况下进行提取.

Should do it - it extracts the data into two groups "Value" and "Date" which you can pick up without the remaining rubbish.

//Use substring expects arg starting length
string str = ("\"20v2015-04-13\"")
//for your ans try this
string strDate = str.Substring(5, 10); 

//OR
//see below link

http://csharp.net-informations.com/string/files/print/csharp-string-substring_print.htm [ ^ ]

http://csharp.net-informations.com/string/files/print/csharp-string-substring_print.htm[^]

Retrieves a substring from this instance. The substring starts at a specified character position and has a specified length. 

作为解决方案1的补充，它为您提供了适合您需求的正则表达式，这是在C#中使用正则表达式的方式:

In complement to solution 1, which gives you an appropriate regular expression for your requirement, here is the way to use a regular expression in C#:

using System.Text.RegularExpressions;

string original = "20v2015-04-13";
Regex r = new Regex(@"(?<value>\d+)[a-zA-Z](?<date>\d{4}-\d\d-\d\d)", RegexOptions.Compiled | RegexOptions.CultureInvariant);
Match m = r.Match(original);
string value = String.Empty;
string date = String.Empty;
if (m.Success) {
   value = m.Groups["value"].Value;
   date = m.Groups["date"].Value;
}

有关.NET中正则表达式的更多信息，请访问:
System.Text.RegularExpressions命名空间 [ ^ ]

More on regular expressions in .NET here:
System.Text.RegularExpressions Namespace[^]

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