泽西JAX-RS客户端XML到java.util.List的反序列化 [英] Jersey JAX-RS Client XML to java.util.List deserialization

问题描述

我正在尝试访问JAX-RS服务(球衣实现)，该服务以XML格式返回了一个Employees的java.util.list.

I am trying to access a JAX-RS Service (jersey implementation) which is returning me a java.util.list of Employees in XML format.

Service方法签名如下:

The Service method signature looks like this:

@GET
@Path("/getEmployeeListXML")
@Consumes(MediaType.TEXT_PLAIN)
@Produces(MediaType.APPLICATION_XML)
public List<EmployeeXML> getEmployeeListXML(@QueryParam("id") String id){
    //Some code which returns a List<EmployeeXML>
}

返回的XML格式如下:

The format of the XML returned is like this:

<employeeXMLs>
    <employeeXML>
            <empId>1</empId>
            <empName>John</empName>
            <empAge>35</empAge>
            <empSex>Male</empSex>
    </employeeXML>
    <employeeXML>
            <empId>2</empId>
            <empName>Lisa</empName>
            <empAge>23</empAge>
            <empSex>Female</empSex>
    </employeeXML>
</employeeXMLs>

要从我的jersey客户端访问此文件，我正在使用以下代码:

For accessing this from my jersey Client, I am using this code:

List<EmployeeXML> empListXML = (List<EmployeeXML>)service.path("rest").path("GetService").path("getEmployeeListXML").accept(MediaType.APPLICATION_XML).get(EmployeeXML.class);

这是不正确的，因为返回类型应该是一个列表，但是在get方法中，目前我正在尝试检索单个对象.我不确定如何在此处从客户端检索列表:(

This is not correct since the return type should be a list but in the get method, presently I am trying to retrieve a single object. I am not sure how to retrieve the List from the client here :(

我遇到此异常:

 unexpected element (uri:"", local:"employeeXMLs"). Expected elements are <{}employeeListXML>,<{}employeeXML>

请帮助我完成这项工作.

Please help me out to make this work.

谢谢

推荐答案

您需要使用'supertype token'来定义客户端类中的返回类型:

You need to use a 'supertype token' to define the return type in your client class:

List<EmployeeXML> empListXML = service
    .path("rest")
    .path("GetService")
    .path("getEmployeeListXML")
    .accept(MediaType.APPLICATION_XML)
    .get(new GenericType<List<EmployeeXML>>() {});

必须使用超类型令牌，才能保留" Jersey在反序列化服务器响应时将使用的通用参数信息.

The supertype token is required in order to 'retain' generic parameter information that Jersey will use when deserializing the server response.

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