在Jenkins管道上的工作区中列出文件 [英] List files on the workspace on a Jenkins Pipeline

问题描述

我正在尝试在Jenkins管道中列出工作区中的文件，以便可以使用它来生成适当的并行任务.

I'm trying to list files in the workspace in a Jenkins Pipeline, so that I can use that to produce appropriate parallel tasks.

虽然我可以简单地使用sh ls > files并阅读它，但我希望我可以使用更复杂的逻辑进一步过滤的File对象.实际上，Files.listFiles(FileFilter)是理想的选择.

While I could simply use sh ls > files and read that, I want File objects which I can filter further with more complex logic. In fact, Files.listFiles(FileFilter) would be ideal.

但是，我根本无法获得文件列表.首先，我不得不求助于一些奇怪的东西，以简单地找到构建的当前工作目录:

However, I can't get the list of files at all. First, I had to resort to some weird stuff to simply find out the current work directory for the build:

sh 'pwd > workspace'
workspace = readFile('workspace').trim()

现在我称之为检索文件列表:

Now I call this to retrieve the list of files:

@NonCPS
def getFiles(String baseDir) {
    Arrays.asList(new File(baseDir).listFiles())
}

并在asList上获得NPE，这意味着，根据我对javadoc的阅读，new File(baseDir)不存在(或不是目录).

And get a NPE on asList, which means, by my read of the javadoc, that new File(baseDir) does not exist (or is not a directory).

我将其标记为@NonCPS，因为它是Pipeline上Groovy闭包所必需的，我真的更希望在完整的Java< 1.8语法上使用它.

I'm tagging it @NonCPS because it's required for groovy closures on Pipeline, which I'd really prefer to use over full java <1.8 syntax.

推荐答案

对于pwd，您可以使用

For pwd you can use pwd step.

关于主工作区目录中的文件列表，您可以使用

As for list of files in main workspace dir you could use findFiles:

files = findFiles(glob: '*.*')

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