Jenkins Shell字符串引用替换 [英] Jenkins shell string quotation replacement

问题描述

我有一个带有执行Shell框的Jenkins作业.在execute shell中，我使用bash而不是破折号(sh).在execute shell中，我有一些应该被解释为包含转义序列的字符串(在本例中为新行:\n)，因此这里是一个示例execute shell:

I have a Jenkins job with an execute shell box. In the execute shell I use bash instead of dash (sh). In the execute shell I have strings which are supposed to be interpreted as they contain escape sequences (in this case the new line: \n), so here is an example execute shell:

#!/bin/bash
set -x #echo on
git fetch
...

git commit -m "Merging $DEVELOPEMENTBRANCH into $INITIALBRANCH\n\nThis is an example second paragraph."
...

我的问题是Jenkins解释/替换了脚本块，改变了它的行为，具体来说，它替换了变量并将双引号替换为单引号，因此在控制台输出中看起来像这样:

My problem here is that the script block is interpreted/replaced by Jenkins in a way that it changes its behavior, to be specific it replaces the variables and replaces the double quotes with single quotes so in the console output it looks like this:

[4] $ /bin/bash /tmp/hudson7542128982632971668.sh
+ git fetch
...

+ git commit -m 'Merging my_feature into develop\n\nThis is an example second paragraph'
...

但是由于单引号，因此不会解释\n部分.这有什么窍门?我想保留双引号或至少解释\n序列.

But in this way the \n part won't be interpreted because of the single quotes. What is the trick here? I want to preserve the double quotes or at least interpret the \n sequences.

推荐答案

git commit -m "A multi-line\n\ncommit message"不会产生多行 仍然提交消息.提交消息的字面意义为A multi-line\n\ncommit message. 双引号不会导致bash解释printf转义序列.

git commit -m "A multi-line\n\ncommit message" will not produce a multi-line commit message anyway. The commit message will be, literally, A multi-line\n\ncommit message. Double-quotes do not cause bash to interpret printf escape-sequences.

要获取多行提交消息，您需要:

To get a multi-line commit-message you need:

git commit -m "`printf \"A multi-line\n\ncommit message\"`"

这在Jenkins shell步骤中很好用.

This works fine in a Jenkins shell step.

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