如果今天有另一份工作至少执行一次，请运行詹金斯的工作 [英] Run Jenkins job if another job ran at least once today

问题描述

我想设置一个每天晚上运行的Jenkins作业(我们称之为A)，并检查是否另一个Jenkins作业(我们称之为B)今天至少成功运行了一次.我不希望B触发A，因为B每天可能运行多次，但是我希望A仅运行一次-如果B不运行，则根本不运行.

I want to set up a Jenkins job (let's call it A) that would run nightly and check if another Jenkins job (let's call it B) ran successfully at least once today. I don't want B to trigger A because B may run multiple times per day, but I want A to run only once--and not to run at all if B did not run.

我考虑过使用条件步骤"选项，但是我不确定如何配置条件.我知道检查另一个作业的构建时间戳的唯一方法是通过Jenkins restful API，但是如果我通过shell中的curl命令执行此操作，则必须公开Jenkins用户的密码，而我不想这样做(更不用说必须在shell中解析json输出了，我也宁愿避免这样做).

I thought of using the "Conditional step" option, but I'm not sure how to configure the condition. The only way I know of to examine the timestamps for another job's builds is via Jenkins restful API, but if I do it via curl commands in shell, I'd have to expose the Jenkins user's password, which I don't want to do (not to mention having to parse the json output in shell, which I would also rather avoid doing).

有什么建议吗?

推荐答案

您可以使用

You can implement such things nicely with the Script SCM plugin:

• 您基本上将对作业"A"执行SCM轮询"步骤，并将其作为检查作业"B"是否成功运行的常规脚本
• 然后将"A"的SCM轮询间隔设置为每晚一次.

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