在JSON中创建父属性 [英] Creating Parent Property in JSON
问题描述
我需要从同一对象创建JSON的父级和子级属性,这意味着它应该类似于
I have requirement to create a parent and child property of JSON from same object which means it should be like
{"employee": {
"name":"skanda",
"id":"123",
"employee":[
{"id":"345"}
]
}
}
这是我的Java对象.请让我知道我该怎么做.我是否应该创建内部类并具有一个以上Employee对象的实例.请指教.我必须以这样的方式进行设计:当通过Rest WS传递时,也应在另一端对它进行反序列化.如果我可以使用注释,请告知在这种情况下应使用哪些注释.
Here is my Java Object. Please let me know how can I do this. Should I create Inner classes and have instance of one more Employee object. Please advise. I have to design in such a way that the same should also be De-serialized on other end when passed through Rest WS. If I can use annotations please advise which annotations should be used in this case.
public class Employee {
private String name;
private String id;
private List<Employee> list = new ArrayList<Employee>();
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public List<Employee> getList() {
return list;
}
public void setList(List<Employee> list) {
this.list = list;
}
}
推荐答案
您可以使用Jackson和注释.您将需要"jackson-databind".
You can use Jackson and annotations. You will need "jackson-databind".
在Maven上,添加如下所示的依赖项:
On maven, add the dependency like this:
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.4.4</version>
</dependency>
使用这样的POJO:
import java.util.List;
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.JsonRootName;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
@JsonRootName(value = "employee")
@JsonIdentityInfo(generator = ObjectIdGenerators.IntSequenceGenerator.class, property = "@id")
public class Employee {
private String name;
private String id;
private List<Employee> employee;
public String getName() {
return name;
}
public void setName(final String name) {
this.name = name;
}
public String getId() {
return id;
}
public void setId(final String id) {
this.id = id;
}
public List<Employee> getEmployee() {
return employee;
}
public void setEmployees(final List<Employee> employee) {
this.employee = employee;
}
}
还有这样的例子:
import java.util.ArrayList;
import java.util.List;
import org.junit.Assert;
import org.junit.Test;
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
public class EmployeeTest {
private static final String EXPECTED_JSON_RESULT = "{\"employee\":{\"@id\":1,\"name\":\"skanda\",\"id\":\"123\",\"employee\":[{\"@id\":2,\"id\":\"345\"}]}}";
@Test
public void serializationTest() throws JsonProcessingException {
final Employee emp1 = new Employee();
emp1.setId("123");
emp1.setName("skanda");
final Employee empL1 = new Employee();
empL1.setId("345");
final List<Employee> list = new ArrayList<>();
list.add(empL1);
emp1.setEmployees(list);
final ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setSerializationInclusion(Include.NON_NULL);
objectMapper.configure(SerializationFeature.WRAP_ROOT_VALUE, true);
Assert.assertEquals(EXPECTED_JSON_RESULT, objectMapper.writeValueAsString(emp1));
}
}
将生成这样的JSON:
Will generate a JSON like this:
{
"employee":{
"@id":1,
"name":"skanda",
"id":"123",
"employee":[
{
"@id":2,
"id":"345"
}
]
}
}
@JsonIdentityInfo
将帮助您进行自我参考,避免使用StackOverflowError
,并且已针对@id
属性进行了映射.您可以根据需要删除.
@JsonIdentityInfo
will help you on self-references, avoiding StackOverflowError
and is mapped for @id
property. You can remove, if you want.
有关完整文档,请参见 https://github.com/FasterXML/jackson
For complete documentation, see https://github.com/FasterXML/jackson
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