mysql加入2个表的结果 [英] mysql join 2 table results
本文介绍了mysql加入2个表的结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有3张桌子:
站点:ID,名称
关联:site_id,assoc_type,assoc_id
选项:ID,名称
Sites: ID, name
Assoc: site_id, assoc_type, assoc_id
Options: ID, name
我想一次执行以下查询
SELECT * FROM sites
FOREACH site SELECT * FROM assoc WHERE assoc_type='option' AND site_id = site.ID
FOREACH assoc SELECT name FROM options WHERE ID = assoc.ID
FOREACH SITE
echo name, array(option 1, option2, option3);
这可能吗?
我要缩短的代码
$getsites = mysql_query("SELECT * FROM sites")or die(mysql_error());
while($row = mysql_fetch_array($getsites)){
echo $row['name'];
$getassoc = mysql_query("SELECT * FROM assoc WHERE type='options' AND site_id = '$row[ID]'")or die(mysql_error());
echo'<ul>';
while($subrow = mysql_fetch_array($getassoc)){
$getoption = mysql_query("SELECT * FROM options WHERE ID = '$subrow[assoc_id]'")or die(mysql_error());
$option = mysql_fetch_assoc($getoption);
echo '<li>'.$option['name'].'</li>';
}
echo'</ul><br/>';
}
推荐答案
SELECT s.name
, ( SELECT o.name
FROM Options AS o
JOIN Assoc AS a
ON a.assoc_id = o.ID
WHERE a.site_id = s.id
AND a.assoc_type='option'
ORDER BY o.id
LIMIT 1 OFFSET 0
) AS option1
, ( SELECT o.name
FROM Options AS o
JOIN Assoc AS a
ON a.assoc_id = o.ID
WHERE a.site_id = s.id
AND a.assoc_type='option'
ORDER BY o.id
LIMIT 1 OFFSET 1
) AS option2
, ( SELECT o.name
FROM Options AS o
JOIN Assoc AS a
ON a.assoc_id = o.ID
WHERE a.site_id = s.id
AND a.assoc_type='option'
ORDER BY o.id
LIMIT 1 OFFSET 2
) AS option3
FROM Sites AS s
如果要对3个表执行通常的联接,要查找所有站点和相关选项,可以使用:
If you want to perform a usual join of the 3 tables, to find all sites and related options, you can use:
SELECT s.name AS site
, o.name AS option
FROM Sites AS s
JOIN Assoc AS a
ON a.site_id = s.id
JOIN Options AS o
ON o.ID = a.assoc_id
WHERE a.assoc_type = 'option'
ORDER BY s.name
, o.name
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