SQL查询以获取2个表中数据的总和 [英] Sql query to get data diffrence of total in 2 tables

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本文介绍了SQL查询以获取2个表中数据的总和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个表:

  1. booking-记录订单明细

id | booking_amount
-------------------
1  |            150
2  |            500
3  |            400

  • payment-记录订单付款

  • payment - records the payment for order

    id | booking_id | amount
    ------------------------
    1  |          1 |    100
    2  |          1 |     50
    2  |          2 |    100
    

  • 我想查找所有付款未完成的预订.根据上述数据,我们希望答案为2,3,因为booking_id=1的付款总额与booking_table中的相应booking_amount相匹配.

    I want to find all bookings where the payments are not complete. With the above data, we expect the answer to be 2,3, because the sum of payments for booking_id=1 matches the corresponding booking_amount in the booking_table.

    推荐答案

    要回答您的问题,您需要考虑两件事:

    To answer your question, you have 2 things you need to think about :

    1. 您想要每个预订行在表payment中的总金额

    您想将booking_amount表与payment联接.


    第1部分非常简单:


    Part 1 is quite simple:

    SELECT sum(amount) as TotalP, booking_id FROM payment GROUP BY booking_id
    

    只是具有简单聚合函数的基本查询...

    Just a basic query with a simple aggregate function...

    对于第2部分,我们希望加入booking_amountpayment;基本的JOIN将是:

    For part 2, we want to join booking_amount and payment; the basic JOIN would be:

    SELECT * FROM booking b 
    LEFT JOIN payment p ON b.id = p.booking_id
    

    我们执行LEFT JOIN是因为我们可能有一些不在payment表中的预订.对于这些预订,您将获得NULL值.我们将使用COALESCENULL值替换为0.

    We do a LEFT JOIN because we may have some booking who are not in the payment table. For those bookings, you will get NULL value. We will use a COALESCE to replace the NULL values by 0.

    最终查询是这样:

    SELECT b.id, COALESCE(TotalP, 0),  b.booking_amount
    FROM
     booking b
    LEFT JOIN
     (SELECT sum(amount) as TotalP, booking_id FROM payment GROUP BY booking_id) as T
    ON  b.id = T.booking_id
    WHERE COALESCE(TotalP, 0) < b.booking_amount
    

    这篇关于SQL查询以获取2个表中数据的总和的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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