jqGrid根据单元格值对Grid中的整行着色 [英] jqGrid Coloring an entire line in Grid based upon a cells value

问题描述

我知道它曾经被问过，但是我无法运行它，而且我没有尝试的余地.

I know it's been asked before, but I cant get it to run and I'm out of things to try.

如果值不为1，我想给Grid中的一行着色-为此，我使用了自定义格式程序.格式化程序本身可以工作，这不是问题.

I want to colorize a row in a Grid if its value is not 1 - I use a custom formatter for this. The formatter itself works, that's not the problem.

到目前为止，我已经尝试了多种在网络上找到的方法-添加类，使用setRowData，使用setCell ...直接添加CSS代码.

I've tried multiple ways I've found so far on the web - adding a class, directly adding CSS code, using setRowData, using setCell....

这是我的示例-没有一个对我有用(Linux，ff363)-任何指针都将不胜感激.

Here are my examples - none of them worked for me (Linux, ff363) - any pointer would be greatly appreciated.

27.05.2010_00:00:00-27.05.2010_00:00:00是我的行ID

27.05.2010_00:00:00-27.05.2010_00:00:00 is my row id

<style>
.state_inactive {
            background-color: red !important;
        }
.state_active {
    background-color: green !important;
}
</style>

function format_state (cellvalue, options, rowObject)
{
    var elem='#'+options.gid;
    if (cellvalue != 1) {

        jQuery('#list2').setRowData(options.rowID,'',
                                    {'background-color':'#FF6F6F'});

        jQuery('#list2').setRowData('27.05.2010_00:00:00-27.05.2010_00:00:00',
                                    '',{'background-color':'#FF6F6F'});

        for (var cnt=0;cnt<rowObject.length;cnt=cnt+1) {
            jQuery(elem).setCell(options.rowId,cnt,'','state_inactive','');

            jQuery(elem).setCell('"'+options.rowId+'"',cnt,'','state_inactive');

            jQuery(elem).setCell('"'+options.rowId+'"',cnt,'5',
                                 {'background-color':'#FF6F6F'},'');
        }
    } else {
        for (var cnt=0;cnt<rowObject.length;cnt=cnt+1) {
            jQuery(elem).setCell(options.rowId,cnt,'','state_active','');
        }
    }
    <!-- dont modify, we simply added the class above-->
    return cellvalue;
}

推荐答案

在我看来，您的主要问题是您没有设置背景颜色"样式.您应该从行中删除"ui-widget-content"类(来自<tr>元素)

It seems to me that your main problem is you're not setting a 'background-color' style. You should remove 'ui-widget-content' class from the row (from <tr> element)

jQuery("#"+ options.rowId,jQuery('#list2')).removeClass('ui-widget-content');

在添加类state_activ或state_inactive之前，因为jQuery UI类'ui-widget-content'是像这样定义的

before adding the class state_activ or state_inactive, because jQuery UI class 'ui-widget-content' is define .ui-widget-content like

{
border: 1px solid #fad42e;
background: #fbec88 url(images/ui-bg_flat_55_fbec88_40x100.png) 50% 50% repeat-x;
color: #363636;
}

并且仅在CSS 'background-color'的设置下，您并不会真正更改背景颜色.因此，尝试使用类似

and only with setting of CSS 'background-color' your not really change the background color. So try to use something like

var trElement = jQuery("#"+ options.rowId,jQuery('#list2'));
trElement.removeClass('ui-widget-content');
trElement.addClass('state_active');

这篇关于jqGrid根据单元格值对Grid中的整行着色的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！