多个jQuery-UI滑块的组合总数 [英] Combined total for multiple jQuery-UI Sliders

问题描述

我正在尝试实现一个页面，其中有4个jQuery-UI滑块，并且我想做到这一点，以便所有4个滑块的总和永远不会超过400.

I'm trying to implement a page where there are 4 jQuery-UI sliders, and I want to make it so the combined total of all 4 sliders will never go over 400.

我不介意该方法的实现方式，它可以从0开始，并且一旦您更改1滑块，剩余的可用总量就会减少，或者将滑块设置为超过最大值，则会减小另一个值滑块.

I don't mind which way this is implemented, it can be from a 0 start, and as soon as you change 1 slider, the remaining available total decreases or setting a slider past the maximum, decreases the values on the other sliders.

P.S.滑块以10为增量.

P.S. The sliders go in increments of 10.

所有创意&欢迎提出建议，如果您要测试，我已经设置了 jsFiddle .

All ideas & suggestions are welcome, and I've set up a jsFiddle if you'd like to test.

推荐答案

在这里开始吧:

var sliders = $("#sliders .slider");

sliders.each(function() {
    var value = parseInt($(this).text(), 10),
        availableTotal = 400;

    $(this).empty().slider({
        value: 0,
        min: 0,
        max: 400,
        range: "max",
        step: 10,
        slide: function(event, ui) {
            // Update display to current value
            $(this).siblings().text(ui.value);

            // Get current total
            var total = 0;

            sliders.not(this).each(function() {
                total += $(this).slider("option", "value");
            });

            // Need to do this because apparently jQ UI
            // does not update value until this event completes
            total += ui.value;

            var max = availableTotal - total;

            // Update each slider
            sliders.not(this).each(function() {
                var t = $(this),
                    value = t.slider("option", "value");

                t.slider("option", "max", max + value)
                    .siblings().text(value + '/' + (max + value));
                t.slider('value', value);
            });
        }
    });
});

这里是一个简单的演示: http://jsfiddle.net/yijiang/Y5ZLL /4/

Here's a simple demo of this: http://jsfiddle.net/yijiang/Y5ZLL/4/

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