在JQuery .trigger上传递参数 [英] Passing parameters on JQuery .trigger
问题描述
我正在使用JQuery触发器,但不确定在我的情况下传递参数的正确语法是什么.这是我打电话的地方:
I am using JQuery trigger but am not sure what the correct syntax is to pass parameters in my situation. Here is where I am making the call :
$('#'+controlName).trigger(event);
在这里,我正在进行事件绑定:
Here is where I am doing the event binding :
$(window).on('onPartialRendered', onPartialRendered);
这是我的事件处理程序:
And here is my event handler :
var onPartialRendered = function () {
.....
};
一切正常,直到我尝试传递参数.按照我的示例,正确的方法是什么?
Everything works fine until I try to pass parameters. What would be the correct way to do it as per my example?
推荐答案
第一个参数始终是带有事件名称的字符串,下一个参数是附加数据:
First parameter is always string with event name and next parameters are additional data:
.trigger('foo', [1, 2]);
.on('foo', function(event, one, two) { ... });
特别感谢Rocket Hazmat
Special thanks for Rocket Hazmat
var controller = {
listen: function (event, json, string) {}
};
$('body').trigger('this_works', [{data: [1, 2, 3]}, 'something']);
$('body').on('this_works', function (event, json, string) {
controller.listen(event, json, string);
});
远程部分:
请不要使用这种方式.网络中有很多有关此问题的文章.这会花费很多时间,并且会在网络中产生不必要的流量.请使用这种方式:
Remote partial:
Please do not use this way. There is many article about this problem in network. This take much time and generate unnecessary traffic in network. Please use this way:
var template = $('#templates #example_template').detach();
var clone = template.clone();
clone.find('.some_field').val('new_data');
clone.attr('id', null);
$('table tbody').append(clone);
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