jQuery选择器按名称获取表单 [英] jQuery selector to get form by name

问题描述

我有以下HTML:

<form name="frmSave">...</form>

只知道，我不能修改HTML以添加id或其他内容.

Just to know, I am not able to modify the HTML in order to add an id or something else.

这就是我试图通过其名称获取form元素的原因:

This is what I tried to get the form element by it's name:

var frm = $('form[name="frmSave"]');

console.log(frm);

(但是我相信上面的代码将尝试在form内获取一个具有frmSave名称的子元素，这不是我所需要的.)

(but I believe the above code will try to get a children element with the frmSave name inside the form which is not what I need).

我该如何实现?是否可以仅通过name并使用选择器来获得form?

How can I achieve this, is it possible to get the form by just the name and using a selector?

我在原始代码中做错了方法(在选择器中使用了空格，也就是组合器")，而不是在这里的代码段中，因此jQuery试图获取具有所需名称的所有子元素，而我问自己是什么问题，因为什么也没回来.

I was doing the wrong way in my original code (I was using a space aka "combinator" in the selector) and not in the code snippet from here so jQuery was trying to get any children element with the name needed and I was asking myself what was wrong since nothing was returned.

被接受的答案对此有一个更好的解释，所以一点空间就能改变一切-下次我会正常睡觉:-)

The accepted answer gives a better explanation about this so a little space could change everything - I will sleep properly next time :-)

推荐答案

$('form[name="frmSave"]')是正确的.您提到您以为这样做会使表格中所有名称为frmsave的孩子都得到；仅当表单和选择器之间存在空格或其他组合符时，才会发生这种情况，例如:$('form [name="frmSave"]');

$('form[name="frmSave"]') is correct. You mentioned you thought this would get all children with the name frmsave inside the form; this would only happen if there was a space or other combinator between the form and the selector, eg: $('form [name="frmSave"]');

$('form[name="frmSave"]')的字面意思是查找名称为frmSave 的所有形式，因为不涉及组合器.

$('form[name="frmSave"]') literally means find all forms with the name frmSave, because there is no combinator involved.

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