jQuery:将第n个单词包装成一个范围 [英] jQuery: wrap every nth word in a span
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问题描述
在jquery中是否可以将第n个单词包装在一个跨度中
Is it possible in jquery to wrap each nth word in a span
所以可以说我有html字符串
so lets say I have the html string
<h3>great Prices great Service</h3>
这将被包装如下(每个第二个单词)
this will be wrapped as follows ( each 2nd word )
<h3>great <span>Prices</span> great <span>Service</span></h3>
任何帮助将不胜感激
推荐答案
var h3 = $('h3');
var text = h3.text().split(' ');
for( var i = 1, len = text.length; i < len; i=i+2 ) {
text[i] = '<span>' + text[i] + '</span>';
}
h3.html(text.join(' '));
或
var h3 = $('h3');
var text = h3.text().split(' ');
$.each(text,function(i,val) {
if( i % 2) {
text[i] = '<span>' + val + '</span>';
}
});
h3.html(text.join(' '));
要按照您在注释中的要求处理&
,我创建了一个offset
变量,该变量在遇到任何变量时都会递增.
To deal with &
as you requested in your comment, I created an offset
variable that is incremented whenever one is encountered.
var h3 = $('h3');
var text = h3.text().split(' ');
var offset = 0;
for( var i = 1, len = text.length; i < len; i++ ) {
if( text[i] === '&' ) {
offset++;
} else if( (i-offset) % 2 ) {
text[i] = '<span>' + text[i] + '</span>';
}
}
h3.html(text.join(' '));
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