jQuery-Fancybox和回调 [英] Jquery - fancybox and callback

问题描述

我对fancybox有问题.
我想编写一个在fancybox打开时运行的函数.如何以及何时调用该函数?

I have problem with fancybox.
I want to write a function that will run when the fancybox opened. How and when to call the function?

示例:

function myFunc() {
    alert("Opened!");
}

$('.content a').fancybox({ 
    'hideOnContentClick': false ,
    'callBackOnShow': myFunc(), // This not working! It call function when page is loaded
    'frameWidth': 920,
    'frameHeight': 530
});

推荐答案

使用myFunc代替myFunc().在javascript中，带有parens(和/或args)的函数表示您要调用它.没有它们的函数名称意味着您只想引用该函数(这可能就是fancybox想要的)

Instead of myFunc() use myFunc. In javascript, a function with parens (and/or args) means you want to call it. A function name without them means you just want a reference to that function (which is probably what fancybox wants from you)

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