在不刷新的情况下将PHP变量传递给Jquery [英] Passing PHP variable to Jquery without refresh

问题描述

我对缺乏jquery知识表示歉意.在我正在建立的这个网站中，向用户展示了许多代表植物的缩略图.单击缩略图时，将启动一个jQuery弹出窗口.我想做的是将具有工厂ID的php变量传递到jquery弹出窗口以显示prper信息.任何帮助将不胜感激.谢谢.

I apologize upfront for my lack of jquery knowledge. In this website I am building, a user is presented with a number of thumbnail images representing plants. When a thumbnail is clicked, a jquery popup is initiated. What I would like to be able to do is pass a php variable that has the ID of the plant over to the jquery popup to display the prper information. Any help would be greatly appreciated. Thank you.

http://www.plantcombos.com/header/main_index. php?display = random_mix

推荐答案

使用jQuery AJAX方法从PHP文件收集数据并将其显示在页面上.这非常简单，您可以将所需的任何变量(参数)传递到页面.

Use the jQuery AJAX method to gather data from a PHP file and display it on the page. It is very easy and you can pass any variables (parameters) you like to the page.

http://api.jquery.com/jQuery.ajax/

例如:

// This will send a request to a PHP page
$.ajax({
    url: "http://example.com/test.php",
    dataType: "html",
    success: function(data){
        // Place the returned data into your content
        $('#image').html(data);
    }
});

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