在Android的字符串/ Java的取词 [英] fetch a word in strings Android/Java

问题描述

所以我与Android / Java编程开始。我想尝试找出句子中的一个词。说，在EditText上用户输入一个句子，即我的朋友是个牛仔。该应用程序应该能够检测到字牛仔从字符串数组。即

So I'm beginning with Android/Java programming. I want to try to find a word in a sentence. Say the user inputs in the EditText a sentence i.e. "My friend is a cowboy." The app should detect the word cowboy from a the String array. i.e.

 String[] words = {"cowboy", "animal", "monster"};

这是我已经试过：

 String[] words = {"cowboy", "animal", "monster"};
Boolean b;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    text = (EditText) findViewById (R.id.editText1);
    view = (TextView) findViewById (R.id.textView1);

    ok = (Button) findViewById (R.id.button1);
    ok.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            String string = text.getText().toString();
            b = string.indexOf("cowboy") > 0;
            view.setText(b.toString());
        }
    });

}

但它给我一个虚假的答案。有什么不对我的code？而在IndexOf方法，我不知道如何把字符串数组为。我希望有人能帮助我解决这个问题。谢谢你。

But it's giving me a false answer. What is wrong with my code? And in the indexOf method, I don't know how to put the string array for that. I hope someone will help me fix this problem. Thanks.

推荐答案

请尝试以下操作：

String[] words = {"cowboy", "animal", "monster"};
String s = "My friend is a Cowboy";
boolean check = false;

for (int i = 0; i < words.length; i++) {
    if (s.toLowerCase().contains(words[i].toLowerCase())) {
        check = true;
    } else {

    }
}
if (check) {
     System.out.println("Yes");
} else {
     System.out.println("No");
}

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