使用jQuery，从跨域URL访问json，其中json的格式可能不正确 [英] with jQuery, access json from cross domain url where json may be poorly formed

问题描述

我正在使用jQuery的ajax函数来访问跨域网址.网址将返回json.我正处于发现阶段，但是我认为，因为json值包含多个'&'字符串，所以json eval抛出错误并停止了我的客户端脚本的执行.我得到的错误是未终止的字符串文字".我知道，如果我将返回的json硬编码到本地div中，然后删除&"；字符串(以及几个隐藏的特殊字符)，我可以成功地将json转换为eval. 无论是通过变通方法，还是通过对我的代码进行更正，我该怎么做才能从URL中获取json并将其作为有效的json对象存储在我的客户端javascript中?

I'm using jQuery's ajax function to hit a cross domain url. The url will return json. I'm in the discovery phase with this but I think, because the json values contain several '&quot' strings, the json eval is throwing an error and stopping the execution of my client side script. The error that I get is "unterminated string literal". I know that if I hard-code the returned json by putting it in a local div and remove the '"' strings (and a couple of hidden special characters), I can get the json to eval successfully. Whether through work-around, or through a correction to my code, what can I do to get the json from the url and store it in my client side javascript as a valid json object?

我当前的代码.没有定义的函数(成功，完成，错误，dataFilter)执行:

my current code. none of the defined functions (success, complete, error, dataFilter) execute:

$(function() {
  $.ajax({
  url: "http://www.codemash.org/rest/sessions.json?format=jsonp&callback=?", 
  dataType: "jsonp",
  success: successFunc,
  complete: completeFunc,
  error: errorFunc,
  dataFilter: dataFilterFunc
});

});

function successFunc() { console.log('successFunc(). enter.'); }
function completeFunc() { console.log('complete(). enter.'); }
function errorFunc() { console.log('errorFunc(). enter.'); }
function dataFilterFunc(data, type) { 
  data.replace(/\W/g, ' ');
  return data; 
}

推荐答案

问题是JSONP服务，它完全消除了callback参数.

The problem is the JSONP service, it is dismissing completely the callback parameter.

JSONP 响应只是一个使用callback get参数作为函数名称的函数调用:

A JSONP response is simply a function call using the callback get parameter as the function name:

如果您查看某些JSONP服务的响应，应该是这样的:

If you look the response of some JSONP service, it should be like this:

http://somesite.com/jsonp?callback= myCallback

会返回:

myCallback({/*json*/});

您发布的正在返回 普通 有效 JSON，但不能将其作为 JSONP 处理响应.

While the one you post is returning plain valid JSON, but it cannot be handled as a JSONP response.

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