jQuery get光标所在的元素 [英] jquery get element where the cursor is

问题描述

我正在使用javascript和jquery为我的网站构建一个splittesting工具.现在，我想显示每个元素，当光标经过预览框中的元素时，我想对它进行拆分测试.有可能做这样的事情吗?我整理这样的东西

I'm building a splittesting tool for my website with javascript and jquery. Now I want to show for each elements I want to splittest a little hovermenu when the cursor passes over the element in my previewbox. Is there any possibility to do something like this ? I treid something like this

$('body').hover(function(event){
    console.log(event.target.nodeName);
    // to see if it's showing up the element   
});

，但仅触发一次.因为我不想使用click，因为我也想在锚元素上显示菜单，所以我有点迷路了

but it's only triggering once. As I don't want to use click since I want also to showup the menu on anchor elements I'm a bit lost

推荐答案

我相信您要在此处使用mousemove事件而不是hover事件.

I believe you want to use the mousemove event here instead of the hover event.

$('body').mousemove(function(evt){
    console.log(evt.target);
});

请记住要特别小心地使用mousemove.

Just remember to use mousemove with extreme caution.

在此处查看示例.

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