删除或隐藏div(如果为空) [英] Remove or hide a div if it's empty

问题描述

我知道这应该很简单，但无法弄清楚.这是代码.

I know this should be simple but can't figure it out. Here's the code.

<div class="cols lmenu_item1" id="leftMenuWrapper">
<div id="leftmenu"></div>
</div>

如果"leftmenu"为空，我只需要删除"leftMenuWrapper".这就是我一直在使用的东西.

I simply need to remove the "leftMenuWrapper" if "leftmenu" is empty. Here's what I've been using.

$('#leftmenu').empty().remove('#leftMenuWrapper');

很抱歉，如果这是一个简单的问题.有一个星期一！

Sorry if this is a simple question. Having a Monday!

谢谢！

推荐答案

您可以这样做:

$('#leftmenu:empty').parent().remove();

仅当 :empty 时，才选择#leftmenu 将 that 的 .parent() 抓取到

This only selects #leftmenu if it's :empty, and then only grabs the .parent() of that to .remove(). If it wasn't empty, then the first selector won't find anything, or any parent to remove either.

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