如何过滤从ajax返回的html正文? [英] How do I filter body html the returned data from ajax?
问题描述
我的目的是,我想从数据中提取特定的html并仅更新该区域.
My purpose is, I want to take specific html out from data and update that area only.
此链接是旧帖子,但我确实有完全相同的问题.
This link is a old post but I do have the exactly same problem.
链接提供的解决方案是$("[ref=B]").html(data).find( '[ref=A]' );
The solution giving from the link is $("[ref=B]").html(data).find( '[ref=A]' );
但是,如果我这样做的话,整个页面将首先写在<span ref='B'>
上,然后在其中找到选择器.....
However, if I do so, the entire page will write on <span ref='B'>
first then find the selector inside of it.....
仅找到'[ref = A]'的另一种方法是
The alternative way to only find '[ref=A]' is
html = $(data).filter('[ref=B]').find('[ref=A]').html() // this way will work
这些都不起作用
$(data).find('[ref=A]').html();
$(data).filter('[ref=A]').html();
$(data).filter('body').html();
$(data).find('body').html();
HTML
`<body>
<span ref='B'><span ref='A'>abc</span></span>
</body>`
JS
$(function() {
$.get(window.location.pathname + window.location.search, function(data){ alert(data);});
});
返回的数据
<html>
<body>
<span ref='B'><span ref='A'>abc</span></span>
</body>
</html>
我的问题是,是否有一种解决方案,可以从$ .ajax返回的数据中过滤主体的html?喜欢
My question is, is there a solution to filter body`s html from data which returned from $.ajax?? like
body_html = $(data).???????
然后我可以做任何我想做的事,例如
then I can do whatever I want, like
body_html.find('xxxx');
非常感谢您的建议.
推荐答案
您可以使用 DOM .
You can use a DocumentFragment to simulate your html and do your search without appending it to the DOM.
// Create your DocumentFragment to be able to work without DOM
var body_html = document.createDocumentFragment();
// Convert and append data from your jQuery to work with fragment
body_html.appendChild($(data)[0]);
// Now you can select using your jQuery
var $body_html = $(body_html);
// Now you can use the find or whatever you want, like if it was in the DOM
$body_html.find('.foo');
// Or you can append in your current document,
// but attention, after it the fragment reference is erased
$body_html.appendTo(document.body);
// now you need to get reference again from body,
// because your fragment doesn't exists anymore.
// So... if you try:
console.log(body_html); // undefined
console.log($body_html); // jquery over undefined, probably just a jquery useless
// At this point you will need to reference from DOM to continue manipulation
$body_html = $(document.body);
// Now I'm ready to continue the work
// This var is like your DocumentFragment, but already on DOM.
您还可以在jQuery模板$(data).filter('.foo')
中进行过滤,但是正如您在 测试 ,您的效果会下降很多.
You also can do a filter in jQuery templating $(data).filter('.foo')
but as you can see in this tests, your performance will drop a lot.
这篇关于如何过滤从ajax返回的html正文?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!