反转HTML网格数据 [英] Reversing HTML grid data

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本文介绍了反转HTML网格数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个html网格表,可以在js文件中创建该表,看起来像这样

I have a html grid table which creates the table in js file and looks like this

   tbl_html = tbl_html + '<tbody>' +

                         '<td>' + yearconvert(yearr) + '</td>' +
                         '<td>' + starttime+ '</td>' +
                         '<td>' + endtime + '</td>';

有一个循环,给出了year,starttime,endtime的值.它显示得很好,但我想反转在html grid中看到的结果.

There is a loop which gives the value of year ,starttime ,endtime . It displays it well but I want to reverse the result which I see in html grid .

for (var i = 0; i < matrix.length; i++) {
    var starttime= Date.UTC(parseInt(matrix[i].start_time);
    var endtime = Date.UTC(parseInt(matrix[i -1]);
    var year =matrix[i].year;
} 

我想看到最后一行将是第一行,其他如下 例如year,11/2009-10/2009-09/2009-08/2009

I want to see last row will be the first row and others as follow for example year , 11/2009 - 10/2009 - 09/2009 - 08/2009

[edit]也就是说,我只想更改行顺序,而不想更改列[/edit]

[edit] That is to say, I only want to change the row order but not the column [/edit]

有实现它的任何想法吗?

Any idea to achieve it ?

谢谢

推荐答案

如何向后遍历矩阵?

for (var i = matrix.length-1; i >= 0; i--) {
        var starttime= Date.UTC(parseInt(matrix[i].start_time);
        var endtime = Date.UTC(parseInt(matrix[i -1]);
        var year =matrix[i].year;

    tbl_html = tbl_html + '<tbody>' +

                             '<td>' + yearconvert(yearr) + '</td>' +
                             '<td>' + starttime+ '</td>' +
                             '<td>' + endtime + '</td>';
    } 

这篇关于反转HTML网格数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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