jQuery-查找任何级别的所有后代，但找不到这些后代的后代 [英] JQuery - Find all descendants at any level, but not the descendants of those descendants

问题描述

问题:

我正在尝试使用JQuery的.find()在元素的任何级别中查找具有给定属性的所有后代，而不是具有相同属性的那些后代的后代.

I am trying to use JQuery's .find() to find all descendants within an element at any level that have a given attribute, but not the descendants of those descendants with the same attribute.

帮助理解:

JQuery

下面的查询的预期目标是找到元素$("#some_id")中的所有后代(任意级别)，具有some_attribute属性，但找不到具有相同属性的后代.

The intended goal of the query below is find all descendants within element $("#some_id") (at any level) that have some_attribute attribute, but not the descendants of those descendants with the same attribute.

$("#some_id").find("[some_attribute]");

HTML

<span id="some_id" some_attribute>
    <span some_attribute> <!-- SELECT -->
        <span some_attribute> <!-- IGNORE -->
            <span some_attribute> <!-- IGNORE -->
            </span>
        </span>
        <span>
        </span>
    </span>
    <span>
        <span some_attribute> <!-- SELECT -->
            <span>
                <span some_attribute> <!-- IGNORE -->
                </span>
            </span>
            <span some_attribute> <!-- IGNORE -->
            </span>
        </span>
    </span>
    <span>
        <span>
            <span>
                <span some_attribute> <!-- SELECT -->
                </span>
            </span>
        </span>
    </span>
</span>

---

注意:我需要一种通用方法...我的解释会更好！假设我不知道选择器$("#some_id")，我只有该查询的结果.还应考虑到此结果可能指向一个元素，该元素可能位于具有some_attribute属性的另一个元素中.

---

NOTE: I need a generic approach... I explain better! Suppose I don't know the selector $("#some_id") I only have the result of that query. Also consider that this result may refer to an element that may be within another element with the some_attribute attribute.

推荐答案

这是我的解决方案.有关更多说明，请参见下面的代码注释...

Here is my solution. For more explanation see the code notes below...

// NOTE: Find all descendants at any level, but not the descendants of those descendants.
// By Questor
function findDescsNotDescsOfThose(jqPntElOrPntQry, jqFind){
    var jqElInst;
    if (typeof jqPntElOrPntQry === "string" || 
            jqPntElOrPntQry instanceof String) {
    // [Ref.: https://stackoverflow.com/a/9436948/3223785 ]

        jqElInst = $(jqPntElOrPntQry);
    } else {
        jqElInst = jqPntElOrPntQry;
    }
    return jqElInst.find(jqFind)
        .filter(function(){

            // NOTE: We need use ".parent ()" and then ".closest ()", otherwise ".closest ()"
            // will find the element itself if it fits "jqFind". By Questor
            descOfjqFind = $(this).parent().closest(jqFind);

            // NOTE: Checks if it is not descended from any element that also fits
            // in "jqFind". Being descended from an element that also fits "jqFind"
            // checks to see if this element is descended from "jqElInst". By Questor
            if (descOfjqFind.length > 0 && $(descOfjqFind).
                    parent().closest(jqElInst).length === 1) {
                return false
            }

            return true;
    });
}

谢谢！ = D

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