PopOver自动调整位置 [英] PopOver auto adjust placement

问题描述

我正遇到PopOver问题.我希望它在所有位置都自动调整.如果在右侧找不到空间，则会在左侧打开.但我希望它对顶部/底部执行相同的操作.即，如果在顶部找不到空间，则应在底部打开，反之亦然.我没有办法全方位地做到这一点吗?

I am facing an issue with PopOver. I want it to auto adjust at all positions. If it doesn't find space on right side it opens at left. But I want it to do the same thing for top/bottom. i.e if it doesn't find space at top it should open at bottom and vice versa. Isn't there any way I can do it for all sides?

$('[data-toggle="popover"]').popover({
        trigger: 'manual',
        placement: 'auto right'
    })

HTML

<a data-toggle="popover" class="hlpicon" data-html="true" data-trigger="hover" data-container="body" data-content="This will open a popover" data-original-title="" title=""></a>

推荐答案

您应该能够将placement选项用作返回字符串的 string 或函数 strong>:

You should be able to use the placement option as either a string or a function returning a string:

$('[data-toggle="popover"]').popover({
    trigger: 'manual',
    placement: function (context, source) {
        var position = $(source).position();

        if (position.left > 515) {
            return "left";
        }

        if (position.left < 515) {
            return "right";
        }

        if (position.top < 110){
            return "bottom";
        }

        return "top";
    }
});

对于上下文，此代码的来源为

For context, the source of this code is Changing the position of Bootstrap popovers based on the popover's X position in relation to window edge? (which declares attribution to be not required - just adding this as a resource).

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