为什么我的JavaScript函数没有填充数组? [英] Why is my JavaScript function not populating my array?

问题描述

以下代码块成功返回数组值(编号1 130879253000、34756)

The following block of code successfully returns array values (No. 1 130879253000, 34756)

    function getCsv(file_name){
        var array_holder = [];
        $.get(file_name, function(csv, state, xhr) {

            // inconsistency
            if (typeof csv != 'string') {
                csv = xhr.responseText;
            }

            // parse the CSV trades
            var header, comment = /^#/, x;

            $.each(csv.split('\n'), function(i, line){
                if (!comment.test(line)) {
                    if (!header) {
                        header = line;
                    }
                    else {
                        var point = line.split(';'),
                            date = point[0].split('-'),
                            time = point[1].split(':');

                        if (point.length > 1) {
                            x = Date.UTC(date[2], date[1] - 1, date[0], time[2], time[1], time[0]);

                            array_holder.push([
                                x, // time
                                parseFloat(point[2]) // close
                            ]);
                        }
                    }
                }

            }); // each
            alert('No. 1' + array_holder[0]);
        });
        return array_holder;
    }

在下面的代码部分中，我试图调用getCsv，但未得到2号未定义

In the following section of code, I'm trying to call getCsv but I get No. 2 undefined

$(function() {

        var trades  = getCsv('trades.csv');
        var spreads = getCsv('spreads.csv');
        alert('No. 2' + trades[0]);
}

为什么我的数组没有填充?在实际的代码中，我具有上述两个功能，它们按此处列出的顺序彼此相邻.因此，可以正确读取文件，就好像array_holder超出范围并被垃圾回收一样.

Why are my arrays not getting populated? In the actual code I have the above two functions right next to each other in the order listed here. So the files are getting read correctly it's as if array_holder falls out of scope and gets garbage collected.

推荐答案

这是由于$.get()的异步特性引起的.在您发出警报的时候，AJAX请求不一定已经运行.

This is due to the asynchronous nature of $.get(). At the point where you do the alert, the AJAX request has not necessarily run yet.

在请求的成功回调中执行警报，该警报发生在"No.1"警报处.

Do the alerting in the request's success callback, where the "No.1" alert takes place.

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