带有jQuery 1.9和Jersey 2.5.1的JSONP [英] JSONP with Jquery 1.9 and Jersey 2.5.1

问题描述

我在Google上搜索了很多东西，但没有找到任何适合我的需求.我在此处，此处和球衣文档.

I've googled a lot and found nothing that suits my needs. I found these similar threads here, here and here, but they don't solve my problem or I don't understand this correctly. I also read the jersey documentation a couple of times.

我正在使用jersey 2.5.1开发服务器端应用程序，并使用HTML/CSS/JavaScript开发客户端.因此，这很不错，但我没有绊脚石. 我正在使用Media-Moxy作为Java2Json映射器.

I'm developing a server side application with jersey 2.5.1 and the client side with HTML/CSS/JavaScript. So for this worked out great, but no I'm stumbling. I'm using Media-Moxy as my Java2Json mapper.

@GET
@JSONP
@Path("search")
@Produces({MediaType.APPLICATION_JSON, "application/javascript"})
public String findByTagsAndBoundingBox(@QueryParam("topLeftLat") Double topLat...) {
    // do some work
    return json.toString();
}

如果我现在在命令行上进行卷曲(请参阅jersey文档的请求，请接受accept标头)

If I now do a curl on the command line (see the accept header as request by jersey documentation)

curl -X GET -H "Accept: application/javascript" "http://localhost:8181/xxxxx/xxxx/search?topLeftLat=59.93704238758132&topLeftLon=10.68643569946289&bottomRightLat=59.890573111743336&bottomRightLon=10.806941986083984&tag=Restaurant&callback=?"

Jersey确实提供了预期的内容(在JSONP中):

Jersey does deliver the content as expected (in JSONP):

callback([{"id":3134,"lon" .... }])

但是如果我这样用jquery调用它:

But if i call this with jquery like this:

$.getJSON("http://localhost:8181/xxxx/yyyy/search?" + query + "&callback=?", function() {
     console.log( "success" );
})

我总是会收到错误消息

 parsererror, Error: jQuery110207164248435292393_1391195897558 was not called 

我可以看到浏览器中的响应包含正确的json，并且得到200返回码.但是由于某种原因，jQuery表示出了问题.

I can see that the response in the browser contains the correct json and I get a 200 return code. But for some reason jQuery says that something is wrong.

我们非常感谢您的帮助， 丹尼尔

Any help is kindly appreciated, Daniel

推荐答案

callback([{应该已经?([{使用了与CURL一起使用的URL.

callback([{ should have been ?([{ using the url you used with CURL.

URL中回调参数的目的是指定应执行的回调函数的名称.例如，jQuery指定&callback=jQuery110207164248435292393_1391195897558应该会导致

The purpose of the callback parameter in the url is to specify the name of the callback function that should be executed. jQuery for example specified &callback=jQuery110207164248435292393_1391195897558 which should result in

jQuery110207164248435292393_1391195897558([{"id":3134,"lon" .... }])

正在从服务中退回.

您需要在服务器代码中更改此行:

You'll need to change this line in your server code:

@JSONP(queryParam = "callback")

ref: https://jersey.java.net/documentation/Latest/user-guide.html#d0e7040

这篇关于带有jQuery 1.9和Jersey 2.5.1的JSONP的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！