如果值已经存在,如何在值的末尾添加字符? [英] how to add characters to the end of the value if it already exists?
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问题描述
在这里,当我单击发布按钮时,它将在数据库中插入一个随机值.
如果数据库上已经存在一个值,则显示错误.它工作正常.
Here when I click post button it inserts a random value on database.
If a value already exists on database then show error. It works fine.
但是我想在值的末尾添加2/3个字符(如果它已经存在于数据库中).如果$check == 1
,那么我想在值的末尾添加一些字符,而不是显示警报.该怎么做?
But I want to add 2/3 characters at the end of value if it already exists on database. If $check == 1
then I want to add some characters at the end of the value instead of showing alert. How to do this?
<?php
$con = mysqli_connect("localhost","root","","post") or die("unable to connect to internet");
if(isset($_POST['submit']))
{
$slug = $_POST['rand'];
$get_slug = "select * from slug where post_slug='$slug' ";
$run_slug = mysqli_query($con,$get_slug );
$check = mysqli_num_rows($run_slug );
// if $check==1 then i want to add 2 characters at the end of $slug .
if($check == 1)
{
// instead of showing alert i want to add 2 more characters at the end of that value and and insert it on database
echo "<script> alert('something is wrong') </script> ";
exit ();
}
else
{
$insert ="insert into slug (post_slug) values ('$slug') ";
$run = mysqli_query($con,$insert);
if($run)
{
echo "<p style='float:right;'> Posted successfully </p>";
}
}
}
?>
<form method="POST" >
<?php
$result = "";
$chars = "abcdefghijklmnopqrstuvwxyz0123456789";
$chararray = str_split($chars);
for($i = 0; $i < 7 ; $i++)
{
$randitem = array_rand($chararray);
$result .= "".$chararray[$randitem];
}
echo $result ;
?>
<input type="hidden" value="<?php echo $result;?>" name="rand" />
<span class="input-group-btn">
<button class="btn btn-info" type="submit" name="submit">POST</button>
</span>
</form>
推荐答案
只需在代码中进行少量修改即可插入新值.
Just few modification in your code to insert new value.
<?php
$con = mysqli_connect("localhost","root","","post") or die("unable to connect to internet");
if(isset($_POST['submit']))
{
$slug = $_POST['rand'];
$get_slug = "select * from slug where post_slug='$slug' ";
$run_slug = mysqli_query($con,$get_slug );
$check = mysqli_num_rows($run_slug );
if($check == 1)
{
$slug_new = $slug.'ab'; // Add 2 characters at the end
$update ="UPDATE slug SET post_slug = '$slug_new' WHERE post_slug = '$slug'";
$run = mysqli_query($con,$update);
}
else
{
$insert ="insert into slug (post_slug) values ('$slug') ";
$run = mysqli_query($con,$insert);
if($run)
{
echo "<p style='float:right;'> Posted successfully </p>";
}
}
}
?>
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