在PHP Echo中调用Javascript函数 [英] Call Javascript Function in PHP Echo
本文介绍了在PHP Echo中调用Javascript函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
参考此链接 ,我正在尝试从表中动态删除行.这是我的Javascript函数:
With reference to This link , I am trying to delete rows dynamically from a table. Here's my Javascript function:
function deleteBox(id){
alert ("Inside Method");
if (confirm("Are you sure you want to delete this record?"))
{
var dataString = 'id='+ id;
$("#flash_"+id).show();
$("#flash_"+id).fadeIn(400).html('<img src="img/loading.gif" /> ');
$.ajax({
type: "POST",
url: "delete.php",
data: dataString,
cache: false,
success: function(result){
if(result){
$("#flash_"+id).hide();
// if data delete successfully
if(result=='success'){
//Check random no, for animated type of effect
var randNum=Math.floor((Math.random()*100)+1);
if(randNum % 2==0){
// Delete with slide up effect
$("#list_"+id).slideUp(1000);
}else{
// Just hide data
$("#list_"+id).hide(500);
}
}else{
var errorMessage=result.substring(position+2);
alert(errorMessage);
}
}
}
});
}
}
但是,从Php中的 Echo 调用它似乎并没有调用它.这是我的PHP代码:
However, calling it from Echo in Php, doesn't seem to invoke it. Here's my PHP code:
echo "<td align=\"center\">" . $id."</td>";
echo "<td><a href = 'javascript:deleteBox($id)'>Delete</a></td>";
无论我哪里出错,都请纠正我.尽早提供帮助将是非常感谢.
Please correct me wherever I'm goin wrong. An early help would be highly appreciated.
推荐答案
<td><a href = 'javascript:deleteBox($id)'>Delete</a></td>
到
echo "<td><a onClick='deleteBox(" . $id . ");'>Delete</a></td>";
在我看来,这就是我的方式.
In my opinion, thats how I would do it..
编辑并缩短了jscript;
Edited and shortened the jscript;
function deleteBox(idDelete){
alert ("Inside Method");
if (confirm("Are you sure you want to delete this record?"))
{
$("#flash_" + idDelete).show();
$("#flash_" + idDelete).fadeIn(400).html('<img src="img/loading.gif" /> ');
$.post('delete.php', {'id': idDelete}, function(result) {
if(result){
$("#flash_" + idDelete).hide();
// if data delete successfully
if(result=='success'){
//Check random no, for animated type of effect
var randNum=Math.floor((Math.random()*100)+1);
if(randNum % 2==0){
// Delete with slide up effect
$("#list_" + idDelete).slideUp(1000);
}else{
// Just hide data
$("#list_" + idDelete).hide(500);
}
}else{
var errorMessage=result.substring(position+2);
alert(errorMessage);
}
}
});
}
在您的delete.php中:
in your delete.php:
$_POST['id']
检索ID.
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