如果页面不存在，则加载特殊页面(404) [英] Load special page if page doesn't exist (404)

问题描述

我有一个小函数(如下)，该函数带有一个参数来确定要加载的内容.我是否可以通过某种方式使.load()遇到"404"错误或回退?

I have a small function (below) that takes a parameter to determine what to load. Is there a way I can make it so that the .load() kind of has an "else" or a fallback if it ecounters a 404?

function start(page,last){
$("#area").load("pages/"+page+".inc.php");
loading();
}

先谢谢您了:)

推荐答案

您可以指定加载完成后要执行的函数.

You can specify a function to be executed when the load completes.

来自 文档 :

$("#success").load("/not-here.php", function(response, status, xhr) {
  if (status == "error") {
    var msg = "Sorry but there was an error: ";
    $("#error").html(msg + xhr.status + " " + xhr.statusText);
  }
});

使用您的代码，它看起来类似于:

Using your code it would look similar to this:

function start(page,last){
    $("#area").load("pages/"+page+".inc.php", function(response, status, xhr) {
        if (status == "error") {
            // don't load as an error occured,...do something else...
        }
        else{
            loading();
        };
    });
}

您可以查看链接的文档，以获取有关可能的返回值和错误的更多详细信息.实际上，文档底部的演示显示了如何处理404.

You can check the linked documentation for more details on possible return values and errors. In fact the demo on the bottom of the documentation shows dealing with a 404.

xhr.status包含错误号404，xhr.statusText为Not Found.

这意味着您可以检查特定的数字:

This would mean you can check for the specific number:

function start(page,last){
    $("#area").load("pages/"+page+".inc.php", function(response, status, xhr) {
        if (status == "error" && xhr.status == ""404) {
            // a 404 occurred...
        }
        else{
            loading();
        };
    });
}

请参见 演示

这篇关于如果页面不存在，则加载特殊页面(404)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！