如何在jQuery中传递参数 [英] How to pass parameters in jquery
问题描述
我应该向另一个页面提交名为str和name的2个值,但是在下一页中仅返回1value.当我包括姓名并在下一页上输入print_r($_POST)
时,即使第一个值也不会被打印.我编写了如下函数,该函数之所以有效,是因为只有一个参数.
I am supposed to submit 2 values called str and name to another page.But only 1value is getting returned in the next page. When I include name and on next page if I say print_r($_POST)
,then even the first value is not getting printed. I have written a function as follows,which works because there is only one parameter.
function sendValue(str)
{
$.post(
"newsletter/subscribe.php", //Ajax file
{
sendValue: str
},
function(data){
$('#display').html(data.returnValue);
},
"json"
);
}
但是,如果我在该函数和$.post
中传递2个值,则执行sendValue:str,name
,那么我什至没有获得1个值.
But if I pass 2 values in that function and in $.post
, I do sendValue:str,name
then I am not getting even 1 value.
推荐答案
您可以发布2个这样的值:
You can post 2 values like this:
function sendValue(str, name) {
$.post("newsletter/subscribe.php",
{ 'string': str, 'name' : name },
function(data){
$('#display').html(data.returnValue);
},
"json");
}
$.post()
的data参数的格式如下:
The format for the data argument of $.post()
is like this:
{ 'varName' : variable, 'var2Name', variable2, 'var3Name' : variable3 }
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