在jQuery中以交替顺序合并两个数组 [英] Merge two arrays in alternating sequence in Jquery

问题描述

我有两个数组A和B，它们都包含许多元素，看起来像这样:

I have two arrays A and B, both of which contain lots of elemets and look like this:

var A = ["A", "B", "C", "D"];
var B = [1, 2, 3, 4];

现在我想要一个数组C，它通过以交替的顺序将它们串联"，从而合并" A和B

Now I want an array C that "merges" A and B by concatenating them in alternating sequence so that

C = ["A", 1, "B", 2, "C", 3, "D", 4]

我尝试过:

for (var i = 0; p < 3; i++) {
    C = A[i].concat(B[i])
}

但这会导致C = "D4".

如何通过交替选择每个数组的一个元素来实现合并两个数组?

How can I achieve that I merge two arrays in by alternately choosing one element of each array?

推荐答案

var l = A.length + B.length,
    C = Array(l);
for(var i=0; i<l; ++i)
    C[i] = (i%2 ? B : A)[i/2|0];

基本上，它会根据i是偶数还是奇数，用A或B中的项目填充C.

Basically, it fills C with items from A or B depending on if i is even or odd.

请注意，我使用i/2|0作为快捷方式，但仅在l严格小于2 ³¹ 时才可以使用.为了安全起见，请使用Math.floor(i/2).

Note I used i/2|0 as a shortcut, but it will only work i l is strictly less than 2³¹. If you want to be safe, use Math.floor(i/2).

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