Push_Notification在Android上的WebServices [英] Push_Notification on Android with WebServices

问题描述

我有一种情况下，它总是与Web服务检查。如果在数据库中的变化那么它应该弹出一个警报消息。我已经做while循环。

 公共无效的onCreate（捆绑savedInstanceState）{    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;    Push_notificaton（）;
        }公共无效Push_notificaton（）{
    而（真）
    {
        尝试
        {
SoapObject请求=新SoapObject（http://tempuri.org/，的getMessage）;SoapSerializationEnvelope信封=新SoapSerializationEnvelope（SoapEnvelope.VER11）;
        envelope.dotNet = TRUE;
        envelope.setOutputSoapObject（请求）;        // Web方法调用
        HttpTransportSE androidHttpTransport =新HttpTransportSE（http://180.215.66.194/WebService.asmx）;
        androidHttpTransport.call（http://tempuri.org/+的getMessage，信封）;
        //得到响应
        SoapPrimitive响应=（SoapPrimitive）envelope.getResponse（）;        //响应对象可通过其名称进行检索：result.getProperty（对象名）;
        字符串消息=（字符串）response.toString（）;
        如果（！currentMsg.equals（消息））
        {
        currentMsg =消息;
        AlertDialog.Builder alertDialogBu​​ilder =新AlertDialog.Builder（本）;            //设置标题
            alertDialogBu​​ilder.setTitle（您的标题）;            //设置对话框消息
            alertDialogBu​​ilder
                .setMessage（单击是退出！）
                .setCancelable（假）
                .setPositiveButton（是，新DialogInterface.OnClickListener（）{
                    公共无效的onClick（DialogInterface对话，诠释的id）{
                        //如果单击此按钮，关闭
                        // 目前的活动
                        MessagesRequestActivity.this.finish（）;
                    }
                  }）
                .setNegativeButton（否，新DialogInterface.OnClickListener（）{
                    公共无效的onClick（DialogInterface对话，诠释的id）{
                        //如果单击此按钮，只要关闭
                        //对话框，什么也不做
                        dialog.cancel（）;
                    }
                }）;                //创建警报对话框
                AlertDialog alertDialog = alertDialogBu​​ilder.create（）;                // 展示下
                alertDialog.show（）;
        alertDialog.setIcon（R.drawable.ic_launcher）;
        alertDialog.show（）;
        }
        Toast.makeText（这一点，消息，Toast.LENGTH_LONG）.show（）;        }
        赶上（例外五）
        {
        e.printStackTrace（）;
        }
 

但在这里我无法获得，因为连续循环播放的输出。让我知道任何其他方式从该克服的。

解决方案

1. 不要做在UI线程的web服务的任何请求。移动你的code到服务或AsyncTask的。前者是更好的。




2. 这方法是耗能的。至少，尽量让睡眠（有时）的请求。

I have a scenario which always checking with the web services. If there is a changes in the DataBase then it should pop-up a alert message . I have done With a WHILE LOOP.

public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Push_notificaton();
        }

public void Push_notificaton(){
    while(true)
    {
        try
        {
SoapObject request = new SoapObject("http://tempuri.org/","getMessage");

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet = true;
        envelope.setOutputSoapObject(request);

        //Web method call
        HttpTransportSE androidHttpTransport = new HttpTransportSE("http://180.215.66.194/WebService.asmx");
        androidHttpTransport.call("http://tempuri.org/"+ "getMessage", envelope);
        //get the response
        SoapPrimitive response = (SoapPrimitive)envelope.getResponse();

        //the response object can be retrieved by its name: result.getProperty("objectName");
        String message = (String)response.toString();
        if(!currentMsg.equals(message))
        {
        currentMsg=message;
        AlertDialog.Builder alertDialogBuilder = new    AlertDialog.Builder(this);

            // set title
            alertDialogBuilder.setTitle("Your Title");

            // set dialog message
            alertDialogBuilder
                .setMessage("Click yes to exit!")
                .setCancelable(false)
                .setPositiveButton("Yes",new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog,int id) {
                        // if this button is clicked, close
                        // current activity
                        MessagesRequestActivity.this.finish();
                    }
                  })
                .setNegativeButton("No",new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog,int id) {
                        // if this button is clicked, just close
                        // the dialog box and do nothing
                        dialog.cancel();
                    }
                });

                // create alert dialog
                AlertDialog alertDialog = alertDialogBuilder.create();

                // show it
                alertDialog.show();
        alertDialog.setIcon(R.drawable.ic_launcher);
        alertDialog.show();
        }
        Toast.makeText(this, message, Toast.LENGTH_LONG).show();

        }
        catch (Exception e)
        {
        e.printStackTrace();
        }

But here I'm unable to get the output because of continuous looping. Let me know any other way to overcome from this.

解决方案

1. Don't do any request to the web-service in ui-thread. Move your code to Service or AsyncTask. The former is better.

2. This approach is energy consuming. At least, try to make requests with sleep(someTime).

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