需要有关jQuery $ .inArray()的帮助 [英] Need help regarding jQuery $.inArray()

问题描述

有人可以告诉我这段代码有什么问题吗?

Could anybody tell me what is wrong with this code ??

jQuery(document).ready(function(){

    var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
    var myArr = ["Weekly", "something"];

    $( myArr ).each(function( j ){
        if ( $.inArray( myArr[j] == val ) ) {
            alert( 'yes, Matched !!' );
            console.log(  myArr[j] );
        } else {
            alert( 'Nops ' );
        }
    });

    //console.log( val );
});

我需要匹配数组元素，我使用了$.inArray()，但是即使数组中不存在它也永远不会达到ELSE条件. 任何帮助将不胜感激.

I need to match the array elements, i used $.inArray(), but it never goes to ELSE condition even it doesn't exist in the array. Any help would be appreciatd.

推荐答案

$.inArray() 接受两个参数，即值和数组，如果找到匹配项，则返回> -1，因此应如下所示:

$.inArray() takes two arguments, the value and the array, and returns > -1 if it finds a match, so it should be like this:

jQuery(document).ready(function(){
   var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
   var myArr = ["Weekly", "something"];
   $.each(myArr, function(i, v) {
     if ($.inArray(v, val) != -1) {
        alert( 'yes, Matched !!' );
        console.log(v);
     } else {
        alert( 'Nops ' );
     }
   });
});

您可以在此处进行测试.还要注意对非元素集使用 $.each() ，没有理由创建无效的jQuery对象来运行循环.

You can test it here. Also note the use of $.each() for non-element sets, no reason creating an invalid jQuery object to run the loop.

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