jQuery函数错误 [英] jQuery function error

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本文介绍了jQuery函数错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是我的代码:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Shout!</title>

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>

<script type="text/javascript">

var status=1;
function action() {



if(status==1) {
$("#Layer1").hide("slow");
$("#Layer3").hide("fast");
$("#Layer4").hide("slow");
$("#close").attr("src","open.jpg");
status=0;

}

else if(status==0) {
status=1;
$("#Layer1").show("slow");
$("#Layer3").show("fast");
$("#Layer4").show("slow");
$("#close").attr("src","close.jpg");

}




}


function sendline() {

$("#msg").val(" ");

}

function type() {
var text=$("#msg").val();

$("#Layer6").html(text);

}

</script>
<style type="text/css">
<!--
    body {
 background-color: #000000;
    }
    #Layer1 {
 position:absolute;
 width:200px;
 height:115px;
 z-index:1;
 left: 179px;
 top: 3px;
    }
    #Layer2 {
 position:absolute;
 width:69px;
 height:64px;
 z-index:2;
 left: 570px;
 top: 543px;
    }
    #Layer3 {
 position:absolute;
 width:124px;
 height:22px;
 z-index:3;
 left: 473px;
 top: 474px;
    }
    .style1 {
 color: #FFFFFF;
 font-family: "Segoe UI";
 font-weight: bold;
    }
    #Layer4 {
 position:absolute;
 width:72px;
 height:27px;
 z-index:4;
 left: 744px;
 top: 485px;
    }
    #Layer5 {
 position:absolute;
 width:274px;
 height:70px;
 z-index:5;
 left: 422px;
 top: 62px;
    }
    #Layer6 {
 position:absolute;
 width:638px;
 height:356px;
 z-index:5;
 left: 272px;
 top: 105px;
    }
-->
</style></head>

<body>
<div class="style1" id="Layer3">
<textarea id="msg" style="height:50px;width:250px" rows="10" cols="80" onkeyup="type()"></textarea></div>
<div id="Layer1">Hello World!<img src="body.jpg" alt="Shout !" width="842" height="554" /></div>
<div id="Layer2"><img src="close.jpg" id="close" width="63" height="64" OnClick="action()"/></div>
<div id="Layer4">
<input type="button" value="Send Line" onclick="sendline()" /></div>
<div id="Layer6" style="color:#FFFFFF;"></div>
</body>
</html>

我遇到了type()函数的问题,它根本没有运行

I'm facing a problem with the type() function.Its simply not running

关于如何得到它的任何建议吗?

Any advice on how to get it rnnning?

谢谢!

推荐答案

您的函数正在运行,但是由于函数名而引发错误:

Your function is running, however it's throwing an error because of the function name:

未捕获的TypeError:字符串不是函数

或在Firefox中:

or in Firefox:

类型不是函数

type is not a function

简而言之,您不能在此处使用type作为函数名称,您只需要给它一个稍有不同的名称即可,例如typed.

In short, you can't use type as a function name here, you just need to give it a slightly different name, for exampled typed.

这是您的代码,仅 更改函数名称,可以正常工作: )

Here's your code only changing the function name, working :)

这篇关于jQuery函数错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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