数据未从表单传输到mysql表(未发生数据更新) [英] Data not transfred from form to mysql table (updating of data is not happening)
问题描述
大家好，谢谢大家
我很累，无法找到答案，我正在寻找答案.我的问题是我无法更新在表单中输入的值.我已经附加了我正在使用MYSQL数据库读取数据的所有文件.
I tired and was unable to find the answer i am looking for an answer. my problem is that i am unable to update the values enterd in the form. I have attached all the files i'm using MYSQL database to fetch data.
发生的事情是，我能够使用Ajax和PHP脚本向MYSQL数据库添加和删除表单中的记录，但是我无法更新从数据库中检索到的数据. 文件结构如下
what happens is that i'm able to add and delete records from form using ajax and PHP scripts to MYSQL database, but i am not able to update data which was retrived from database. the file structure is as follows
index.php 是一个具有Ajax功能的文件，在其中显示用于使用save.php文件向MYSQL添加新数据的表单，并且所有记录的列表都可以在不刷新页面的情况下查看(称为加载列表). php可以从index.php查看所有记录，并且可以使用save.php来保存表单中的数据)
index.php is a file with ajax functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refrishing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form)
-> 删除是一个从index.php调用的ajax函数，用于从mysql数据库中删除记录(调用delete.php的函数工作正常)
-> Deleteis an ajax function called from index.php to delete record from mysql database (function calling delete.php works fine)
-> 更新是从index.php调用的ajax函数，可通过从mysql表格中检索特定记录来使用update-form.php更新数据，(工作正常)
-> Update is an ajax function called from index.php to update data using update-form.php by retriving specific record from mysql tabel, (works fine)
问题在于更新数据 update-form.php到update.php(其中 更新查询已写入mysql)
Problem lies in updating data from update-form.php to update.php (in which update query is wrriten for mysql)
最后我尝试了很多方法，我发现数据没有从update-form.php传输到update.php，而jquery ajax函数存在一个小问题，即它没有将数据传输到update.php.页面.
i had tried in many ways at last i had figured out that data is not being transfred from update-form.php to update.php there is a small problem in jquery ajax function where it is not transfering data to update.php page.
任何人都可以纠正这个问题吗????我对他们非常满意. 请在下面找到所有文件的链接
can any one correct this ????? i will be greatfull to them..... please find the link below for all files
推荐答案
我编写了一个程序，但是它没有用"
"I wrote a program and it isn't working"
对此问题的一般回答只有一个:调试.
该术语代表一种技术，它使程序员可以在代码中发现错误.
实际上，调试花费了大部分时间来开发程序.去图吧.
要其他人为您调试代码就是要他们为您完成工作.免费.
The general answer to such a question is only one: debugging.
This term stands for a technique that allows a programmer to find an error in the code.
As a matter of fact, debugging take most of time spent to develop a program. Go figure.
Asking other people to debug your code for you is to ask them to do your job for you. For free.
如果您不是程序员，请考虑雇用一个.
如果您想成为程序员，请尽快开始学习调试
从这里开始的文章: https://www.ibm.com/developerworks/库/os-debug/
If you aren't a programmer, consider to hire one.
If you wannabe-programmer, start to learn debugging as soon as possible
Here is an article to start: https://www.ibm.com/developerworks/library/os-debug/
由于AJAX应用程序较难调试，因此建议您先编写没有AJAX的应用程序，使其正常运行，然后再实施AJAX程序.
Since AJAX applications are harder to debug, I'd advice to write your app without AJAX first, make it working, and only then implement AJAX bells and whistles.
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