如何在轮询ajax时填充子网格,然后在jqgrid中添加现有网格? [英] How to populate subgrid while polling ajax then apppend existing grid in jqgrid?
问题描述
我有使用代码的列表json列表我想
I have list of list json using the code and got a proper answer also after i want polling every 6 sec append data from db with same list of list json format its also working fine without subgrid system but am integrating both after i got a parent polling data correct but I am not getting the subgrid data its empty(fetch the data backend for subgrid fine).
Oleg评论后第二次更新代码我已附上代码,请找到它
Second time UPDATED CODE after Oleg comments I have attached the code please find it
var $grid = $("#list11"),
mainGridPrefix = "s_";
jQuery("#list11").jqGrid({
url: 'server.php?getList',
datatype: "json",
data: firstListJson,
height: 200,
colNames: ['Inv No', 'Date', 'Client'],
colModel: [{
name: 'id',
index: 'id',
width: 55
}, {
name: 'invdate',
index: 'invdate',
width: 90
}, {
name: 'name',
index: 'name',
width: 100
}],
rowNum: 10,
gridview: true,
rowList: [10, 20, 30],
pager: '#pager11',
loadonce: false,
sortname: 'id',
viewrecords: true,
idPrefix: mainGridPrefix,
sortorder: "desc",
multiselect: false,
caption: "Subgrid With polling",
jsonReader: {
repeatitems: false,
id: 'id'
},
beforeProcessing: function(data) {
var rows = data,
l = data.length,
i, item, subgrids = {};
for (i = 0; i < l; i++) {
item = rows[i];
if (item.subGridData) {
subgrids[item.id] = item.subGridData;
}
}
//alert(subgrids);
data.userdata = subgrids;
},
subGrid: true,
subGridRowExpanded: function(subgridDivId, rowId) {
var subGridID = $("#" + subgridDivId + "_t");
var $subgrid = $("<table id='" + subgridDivId + "_t'></table>"),
pureRowId = $.jgrid.stripPref(mainGridPrefix, rowId),
subgrids = $(this).jqGrid("getGridParam", "userData");
$subgrid.appendTo("#" + $.jgrid.jqID(subgridDivId));
$subgrid.jqGrid({
datatype: "local",
data: subgrids[pureRowId],
colNames: ['Emp ID', 'Name', 'Age'],
colModel: [{
name: 'id',
index: 'id',
width: 55
}, {
name: 'name',
index: 'name',
width: 90
}, {
name: 'age',
index: 'age',
width: 100
}],
rowNum: 10,
rowList: [10, 20, 30],
sortname: 'id',
viewrecords: true,
sortorder: "desc",
multiselect: false
});
}
});
jQuery("#list11").jqGrid('navGrid', '#pager11', {
add: false,
edit: false,
del: false
});
Below code
for json list of list
var firstListJson = [{
"id": "01",
"invdate": "2014-07-24",
"name": "John",
"subGridData": [{
"id": "01",
"name": "Krishna",
"age": "28"
}, {
"id": "01",
"name": "Jai",
"age": "28"
}, {
"id": "01",
"name": "Suresh",
"age": "28"
}]
}, {
"id": "02",
"invdate": "2014-07-24",
"name": "Hill",
"subGridData": [{
"id": "01",
"name": "Mani",
"age": "28"
}, {
"id": "01",
"name": "Raj",
"age": "28"
}, {
"id": "01",
"name": "Main",
"age": "28"
}]
}];
Below code
for polling code
function pollData() {
var pollingListUrl = 'server.php?getPollList';
$.ajax({
type: "POST",
url: pollingListUrl,
contentType: "application/json; charset=utf-8",
dataType: "json",
async: true,
cache: false,
success: function(data) {
var $mygrid = $("#list11");
$mygrid.jqGrid("addRowData", "id", data);
$mygrid.trigger("reloadGrid", [{
current: true
}]);
},
error: function(x, e) {
alert("error occur");
}
});
}
推荐答案
我在您的代码中看到3个错误:
I see 3 errors in your code:
-
您使用
datatype: "xml"
,但是beforeProcessing
的代码针对的是data
是 object 而不是XML-Document的代码.
you use
datatype: "xml"
, but the code ofbeforeProcessing
are oriented on the code wheredata
is object instead of XML-Document.
通过这种方式,我严格建议您在网格和子网格中都添加gridview: true
,以提高性能.
By the way I strictly recommend you to add gridview: true
in both grid and subgrid to improve the performance.
您使用$mygrid.jqGrid("addRowData", "ID", data);
,但是网格不包含列"ID"
.您应该改用"id"
.
You use $mygrid.jqGrid("addRowData", "ID", data);
but the grid don't contain the column "ID"
. You should use "id"
instead.
代替
var firstListJson=[
{"id":"01","invdate":"2014-07-24","name":"John",
"subGridData":"[{
"id":"01","name":"Krishna","age":"28"},
{"id":"01","name":"Jai","age":"28"},
{"id":"01","name":"Suresh","age":"28"}
]"},
{"id":"02","invdate":"2014-07-24","name":"Hill",
"subGridData":"[{
"id":"01","name":"Mani","age":"28"},
{"id":"01","name":"Raj","age":"28"},
{"id":"01","name":"Main","age":"28"}
]"}
];
应该使用
var firstListJson=[
{"id":"01","invdate":"2014-07-24","name":"John",
"subGridData": [{
"id":"01","name":"Krishna","age":"28"},
{"id":"01","name":"Jai","age":"28"},
{"id":"01","name":"Suresh","age":"28"}
]},
{"id":"02","invdate":"2014-07-24","name":"Hill",
"subGridData": [{
"id":"01","name":"Mani","age":"28"},
{"id":"01","name":"Raj","age":"28"},
{"id":"01","name":"Main","age":"28"}
]}
];
如果subGridData
的值将是对象(项目数组)而不是字符串.
In the case the value of subGridData
will be object (array of items) instead of string.
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