防止返回浏览器和警告，需要严格的方法 [英] prevent back in browser and warning, strict way needed
问题描述
我需要防止用户严格切换回上一页.我为您展示示例编码，如下所示:
I need to prevent the user to switch back to previous pages strictly. I show you example coding as follows:
<html>
<head>
<script type="text/javascript">
/* prevent back */
window.history.forward();
function prevent()
{
window.history.forward();
}
/* warning on unload */
window.onbeforeunload = function (e) { var message = 'Are you sure ?'; if (typeof e == 'undefined') { e = window.event; } if (e) { e.returnValue = message; } return message; }
</script>
</head>
<body onload="prevent();" onpageshow="if (event.persisted) prevent();" onunload="">
<!--content here-->
<a href="in.html">in</a>
</body>
</html>
上面的页面具有指向另一页面的链接，如果我在第二页上单击回来，它将返回到第一页并显示警告，然后移至第二页；
The above page have link to another page, if i click back on that second page, it come back to this first page and showing warning and then move to second page;
第二页:
<a href="hello.html">hello</a>
我出于某种原因添加了警告脚本.
I added warning script for some reason.
现在，我真正需要的是.当阻止重新工作时，警告脚本不应工作.
Now, what i need exactly is. When prevent back working, warning script should not work.
1.当用户卸载页面时，应显示警告脚本 2.当防止后退功能卸载页面时，不应显示警告脚本
1.When user unload a page, should show warning script 2.when prevent back function unload the page, should not show warning script
是否有可能以某种严格的方式完全禁止从页面返回?上面的编码不是很严格.它将继续前进.
Is there any way possible to disable going back from a page in all the way, any strict way? the above coding is not much strict. it will move forward on getting back.
谢谢.
推荐答案
是的，鲍伊.
但是，很遗憾，这个婴儿没有回来
第1页
<html>
<head>
<title>if you go, don't come back</title>
</head>
<body>
<!--content here-->
<a href="pageofnoreturn.html#noBack">in</a>
</body>
</html>
pageofnoreturn.html
pageofnoreturn.html
<html>
<head>
<title>Stay put, or else</title>
</head>
<body>
<h1>welcome to purgatory</h1>
<script>
if (location.hash == '#noBack') {
history.pushState(null, '', '#sit');
//whatever hashes that suit your project
window.onhashchange = function() {
if (location.hash == '#noBack') {
history.pushState(null, '', '#sit');
}
}
}
</script>
</body>
</html>
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