jQuery按键37问题，'％'和[左箭头]在IE 10中不起作用 [英] Jquery keypress 37 issue, '%' and [ left arrow ] not work in IE 10

问题描述

早上好

我在IE 10上遇到问题，我的按键仍然可以输入'％'，但是FF和Chrome都没有此问题. 我发现键37是[左箭头]，与ASCII中的'％'相匹配. 我的示例代码如下:

I facing a issue on the IE 10 where my keypress still can enter '%' but the FF and Chrome no such issue. I found out that the key 37 is the [ left arrow ] which match with '%' in ASCII. My sample code as below:

$('#refId').bind("keypress", function(event) {
            // allow  letters, numbers and keypad numbers ONLY
            var key = event.charCode;
            if((key >= 48 && key <= 57) ||
                (key >= 65 && key <= 90) ||
                (key >= 97 && key <= 122)){
                return true;
            }

            //allow backspace, tab, left arrows, right arrow, delete
            key = event.keyCode;
            if(key == 8 || 
                    key == 9 ||
                    key == 37 ||
                    key == 39 ||
                    key == 46){
                return true;
            }

            return false; 
    });

能告诉我一些解决方法吗?

Can give me some idea how to fix this?

谢谢. -fsloke

Thanks. -fsloke

推荐答案

改为使用var key = event.which;并加入if语句.

Use var key = event.which; instead and join the if-statements.

event.which属性规范化event.keyCode和event.charCode. 建议观看事件.该事件用于键盘键输入.

The event.which property normalizes event.keyCode and event.charCode. It is recommended to watch event.which for keyboard key input.

- https://api.jquery.com/event.which/

$('#refId').on("keydown", function(event) {
    // allow letters, numbers and keypad numbers ONLY
    var key = event.which;
    if((key >= 48 && key <= 57) ||
        (key >= 65 && key <= 90) ||
        (key >= 97 && key <= 122) ||
        key == 8 || 
        key == 9 ||
        key == 37 ||
        key == 39 ||
        key == 46) {
        return true;
    }

    return false; 
});

这篇关于jQuery按键37问题，'％'和[左箭头]在IE 10中不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！